因此,当涉及到关系有一个额外列的项目的多对多关系时,我开始挣扎于Doctrine2。
我有以下表格:
技能
profile_has_skills
现在我稍后添加了级别列,并注意到发生了一些问题,当然我每次尝试创建关系时都会丢失级别。 我的问题是,通过下面的代码,我将如何在我的学说中添加这个?
我的控制器:
public function store(Request $request)
{
$time = new DateTime();
$this->validate($request, [
'name' => 'required',
'lastname' => 'required',
'gender' => 'required',
'profile_skills' => 'required'
]);
$this->em->getConnection()->beginTransaction();
try {
$profile = new Profile(
$request->input('company_id'),
$request->input('name'),
$request->input('lastname'),
$request->input('gender'),
new DateTime(),
$time,
$time
);
$company = $this->em->getRepository(Company::class)->find($request->input('company_id'));
$profile->addCompany($company);
foreach($request->input('profile_skills') as $skill => $level) {
$skill = $this->em->getRepository(Skill::class)->find($skill);
$skill->level = $level;
$profile->addSkill($skill);
}
$this->em->persist($profile);
$this->em->flush();
$this->em->getConnection()->commit();
} catch (OptimisticLockException $e) {
$this->em->getConnection()->rollBack();
throw $e;
}
return redirect(route('profiles.index'));
}
我的ProfileHasSkill实体如下所示:
/**
* @ORM\Entity
* @ORM\Table(name="profile_has_skill")
*
*/
class ProfileHasSkill
{
/**
* @ORM\Id
* @ORM\GeneratedValue
* @ORM\Column(type="integer")
*/
protected $id;
/**
* @Column(type="integer", name="profile_id")
*/
protected $profile_id;
/**
* @Column(type="integer", name="skill_id")
*/
protected $skill_id;
/**
* @Column(type="integer", name="level")
*/
protected $level;
/**
* @param $profile_id
* @param $skill_id
* @param $level
*/
public function __construct($profile_id, $skill_id, $level = 0)
{
$this->profile_id = $profile_id;
$this->skill_id = $skill_id;
$this->level = $level;
}
我在配置文件实体中的addSkill方法如下:
public function addSkill(Skill $skill)
{
if ($this->skills->contains($skill)) {
return;
}
return $this->skills->add($skill);
}
但是无论何时我尝试运行它都会给我以下错误
An exception occurred while executing
'INSERT INTO profile_has_skill (profile_id, skill_id) VALUES (?, ?)'
with params [3, 2]: SQLSTATE[HY000]: General error: 1364 Field 'level'
doesn't have a default value
现在我知道摆脱这个错误的一种方法是在数据库中设置一个默认值,但我更愿意找出为什么它没有提升我的技能水平,我也正在传递?
答案 0 :(得分:1)
根据我的解决方案,通过阅读@Nicola Havric传递的另一个问题 - Read as follow该学说不支持多对多关系中的额外列。因此,您应该将关系用作自己的实体。我自己的解决方案是改变我希望它用刷新运行的方式。
在我的控制器中,我更改了我的代码如下:
try {
$profile = new Profile(
$request->input('company_id'),
$request->input('name'),
$request->input('lastname'),
$request->input('gender'),
new DateTime(),
$time,
$time
);
$company = $this->em->getRepository(Company::class)->find($request->input('company_id'));
$profile->addCompany($company);
//Flush the user, so I can grab it's profile ID
$this->em->persist($profile);
$this->em->flush();
foreach($request->input('profile_skills') as $skill => $level) {
$skill = $this->em->getRepository(Skill::class)->find($skill);
$skill->level = $level;
$profile->addSkill($skill);
}
$this->em->getConnection()->commit();
在我的个人资料实体功能中:
public function addSkill(Skill $skill)
{
//I left this check since it only checks if the relation is set already. If so, it will skip it.
if ($this->skills->contains($skill)) {
return;
}
//Since this function gets called inside a loop, I can call the entity to add a new "relation" to the table.
(new ProfileHasSkill($this->getId(), $skill, $skill->level))->addSkill($this->getId(), $skill, $skill->level);
return true;
}
在我的ProfileHasSkill实体中:
public function addSkill($profileId, $skill)
{
//Creating a new ProfileHasSkill inside the table.
$profileSkill = new ProfileHasSkill(
$profileId,
$skill->getId(),
$skill->level
);
/*Since I do a roll-back inside my controller in case something goes wrong.
I decided to add the flush here.
As far no additional checks where needed in my case
since I require a Profile instance and a Skill instance inside the Profile entity.*/
EntityManager::persist($profileSkill);
EntityManager::flush();
}
答案 1 :(得分:0)
具有多对多关系的东西是,除两个表中的两个主键之外的任何其他列都被视为 pivot 列,当将实体附加到此类关系时,您希望使用方法< strong> attach ,它接受id数组作为第一个参数,接受带有 pivot 列的数组,请考虑以下因素。
public function addSkill(Skill $skill)
{
if ($this->skills->contains($skill)) {
return;
}
//Dunno what this method does
return $this->skills->add($skill);
//But this is the correct way of adding a skill
$this->skills->attach($skill->id, ['level' => $skill->level]);
}
希望这可以澄清一些事情,即使以Eloquent为例; here is the manual link代码为上述代码。