Question

我目前正在开发一个Java Web应用程序，它在某个时候从数据库中读取这个xml数据，并尝试使用Java的 Unmarshaller 类将其转换为Object。

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<knowledge idLog="1312" xmlns="http://www.testknowledge.it/knowledge">
    <knowledge_request code="REQUEST_CODE">
        <par type="continuo" data="08-02-2018 15:42:37" code="requestedfor_1" id="">
            <val>ÌÉÀÈÉĒ</val>
        </par>
        <par type="continuo" data="08-02-2018 15:42:37" code="requestedfor_2" id="">
             <val>ÌÉÀÈÉĒ</val>
        </par>
        <par type="continuo" data="08-02-2018 15:42:42" code="gender" id="">
            <val>M</val>
        </par>
    </knowledge_request>
</knowledge>

尝试转换存储在此xml中的信息的Java代码是：

public static Object str2obj(String  str) throws KnowdledgeException {
    try {
        InputStream is = new ByteArrayInputStream(str.getBytes());
        Object o;
        o = unmarshaller.unmarshal(is);
        return o;
    } catch (JAXBException e) {
        throw new KnowdledgeException(e);
    }
}

str 的值基本上是从数据库读取的上述xml数据。和unmarshaller声明：

static {
        try {
            JAXBContext context = JAXBContext.newInstance("it.health.knowledge.data");
            marshaller = context.createMarshaller();
            marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
            marshaller.setProperty(Marshaller.JAXB_ENCODING, "UTF-8");
            // marshaller.setProperty(Marshaller.JAXB_ENCODING, "ISO-8859-1");

            unmarshaller = context.createUnmarshaller();
        } catch (JAXBException e) {
            throw new RuntimeException(
                    "There was a problem creating a JAXBContext object for formatting the object to XML.");
        }
    }

将函数应用于xml数据时引发的异常是： [org.apache.xerces.impl.io.MalformedByteSequenceException：2字节UTF-8序列的字节2无效。]

对于如何解决这个问题的任何想法表示赞赏！

Answer 1

使用unmarshaller.unmarshal(new StringReader(str))。

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