我不知道如何在django中使用反向功能。我得到了这个,
ValueError: dictionary update sequence element #0 has length 1; 2 is required
我可以直接对网址进行硬编码工作正常,但我想以标准方式进行。
主要urls.py
urlpatterns = [
url(r'^nmailadmin/', admin.site.urls),
url(r'^api/v1/',include('Core.Login.urls',namespace='login')),
url(r'^api/v1/mail/',include('Core.Mail.urls',namespace='mail')),
]
我已经为登录和邮件API提供了命名空间。
当我尝试访问此类邮件网址时
def test_0list_folders(self):
url = reverse('mail:folder_list', kwargs={'server':0})
response = self.client.get('/api/v1/mail/folder_list/0/', follow=True)
self.assertEqual(status.HTTP_200_OK, response.status_code)
我收到这样的错误。
----------------------------------------------------------------------
Traceback (most recent call last):
File "/home/next/PycharmProjects/Nmail/Nmail-Server/Core/Mail/tests.py", line 25, in test_0list_folders
url = reverse('mail:folder_list', kwargs={'server':0})
File "/home/next/venv/NmailVenv/lib/python3.6/site-packages/django/urls/base.py", line 91, in reverse
return force_text(iri_to_uri(resolver._reverse_with_prefix(view, prefix, *args, **kwargs)))
File "/home/next/venv/NmailVenv/lib/python3.6/site-packages/django/urls/resolvers.py", line 436, in _reverse_with_prefix
self._populate()
File "/home/next/venv/NmailVenv/lib/python3.6/site-packages/django/urls/resolvers.py", line 309, in _populate
dict(defaults, **pattern.default_kwargs),
ValueError: dictionary update sequence element #0 has length 1; 2 is required
----------------------------------------------------------------------
这是我的邮件应用的网址文件。
urlpatterns = [
url(r'folder_list/(?P<server>\d+)/$', folder_list,name='folder_list'),
url(r'^auth_login/$', login_auth, name='auth_login'),
url(r'viewmsg/(?P<server>\d+)/(?P<folder>.*?)/(?P<uid>\d+)/$', viewmsg, name='viewmsg'),
url(r'action/(?P<action>.*?)/$', action, 'action'),
]
Django版本:Django == 1.11.7
答案 0 :(得分:0)
我的坏。我实际上发现问题是我的一个邮件应用程序 urls.py
中缺少kwarg名称urlpatterns = [
url(r'folder_list/(?P<server>\d+)/$', folder_list,name='folder_list'),
url(r'^auth_login/$', login_auth, name='auth_login'),
url(r'viewmsg/(?P<server>\d+)/(?P<folder>.*?)/(?P<uid>\d+)/$', viewmsg, name='viewmsg'),
url(r'action/(?P<action>.*?)/$', action, name='action'),
]
这一切都很好。希望这有助于将来。
P.S:答案Error: "dictionary update sequence element #0 has length 1; 2 is required" on Django 1.4已经指出了这一点。