从xQuery返回所有可能的值

时间:2018-02-08 12:04:54

标签: sql sql-server xquery xquery-sql

如果我手动选择特定的实例,例如[1],[2]等,我有下面的代码可以返回维修费用。

我想知道是否可以动态返回所有项目

    select
        *
        ,Data1.Data.value('(/PurchaseModel//DamageModel/Damage/RepairCost)[1]', 'Float')
        ,Data1.Data.value('(/PurchaseModel//DamageModel/Damage/RepairCost)[2]', 'Float')
        ,Data1.Data.value('(/PurchaseModel//DamageModel/Damage/RepairCost)[3]', 'Float')
        ,Data1.Data.value('(/PurchaseModel//DamageModel/Damage/RepairCost)[4]', 'Float')
        ,Data1.Data.value('(/PurchaseModel//DamageModel/Damage/RepairCost)[5]', 'Float')
        ,Data1.Data.value('(/PurchaseModel//DamageModel/Damage/RepairCost)[6]', 'Float')
        ,Data1.Data.value('(/PurchaseModel//DamageModel/Damage/RepairCost)[7]', 'Float')
    FROM
        #Data

3 个答案:

答案 0 :(得分:3)

您必须使用动态SQL,以下是如何构建此类查询一次,然后自动生成它:

--you can omit declarations of these integers if you know limits of an index
declare @start int, @end int, @query nvarchar(1000)
select @start=1, @end=7, @query = 'select *'
--generate indexes that you want to retrieve
;with cte as (
  select @start [n]
  union all
  select [n] + 1 from cte where n < @end
)
--construction of actual query, that you want to execute
select @query = @query + replace(', Data1.Data.value(''(/PurchaseModel//DamageModel/Damage/RepairCost)[@index]'', ''Float'')', '@index', cast(n as nvarchar(3))) from cte

sp_executesql @query + N' from #Data'

答案 1 :(得分:0)

您可以使用xml方法节点和值,如下所示:

DECLARE @xml xml =
'<PurchaseModel>
    <DamageModel>
        <Damage>
            <RepairCost>100.00</RepairCost>
            <RepairCost>200.00</RepairCost>
            <RepairCost>300.00</RepairCost>
            <RepairCost>400.00</RepairCost>
            <RepairCost>500.00</RepairCost>
            <RepairCost>600.00</RepairCost>
            <RepairCost>700.00</RepairCost>
            <RepairCost>800.00</RepairCost>
            <RepairCost>900.00</RepairCost>
            <RepairCost>1000.00</RepairCost>
        </Damage>
    </DamageModel>
</PurchaseModel>'


select row.value('.','float') as repaircost
from @xml.nodes('(/PurchaseModel//DamageModel/Damage)') a(damage)
cross apply damage.nodes('RepairCost') bar(row)

返回:

repaircost
----------
100
200
300
400
500
600
700
800
900
1000

答案 2 :(得分:0)

使用以下代码,您将拥有一个包含XML文件所有值的Select命令。之后你可以将它插入到某个表中。

EXEC sp_xml_preparedocument @hDoc OUTPUT, @XML

SELECT RankID,RankName,RankShort,@id
FROM OPENXML(@hDoc, '/PurchaseModel//DamageModel/Damage')
WITH (  RepairCost int 'RepairCost ')

EXEC sp_xml_removedocument @hDoc