Question

我正在尝试返回名称＆amp;评分等级第三高的学生的成绩。我目前正在得到正确的答案，但我觉得有更好的方法来做到这一点。

数据集

CREATE TABLE Student( Student_ID INT, Student_Name VARCHAR(10) ) INSERT INTO Student (Student_ID, Student_Name) VALUES (1,'Alex'),(2, 'Brett1'),(3,'Cora'),(4,'David'),(5,'Eleanor'),(6,'Brett2')

CREATE TABLE Grades( Student_ID INT, Assignment_ID INT, Grade INT ) INSERT INTO Grades (Student_ID, Assignment_ID, Grade) VALUES (1,10,90),(2,10,85),(3,10,75),(4,10,74),(1,11,80),(2,11,81),(4,11,88),(6,11,86),(2,12,84)

尝试解决方案

SELECT top 1 s.Student_Name, g.Grade FROM Student s INNER JOIN Grades g on s.Student_ID=g.Student_ID WHERE g.Grade < 88 ORDER BY Grade DESC

没有（WHERE g.Grade＆lt; 88）它返回前3个结果，这是解决问题的手动方法

提前致谢〜！

Answer 1

只获得第3名，你可以使用前3名的TOP 1回复

  select top 1 Student_name, Grade 
  from ( 
    SELECT top 3 s.Student_Name, g.Grade
      FROM Student s
      INNER JOIN Grades g on s.Student_ID=g.Student_ID
      ORDER BY Grade DESC ) t
      order by Grade asc

Answer 2

＆＃34;较新的＆＃34; SQL Server版本（SQL Server 2012 +）：

SELECT s.Student_Name, g.Grade
FROM Student s
INNER JOIN Grades g on s.Student_ID=g.Student_ID
ORDER BY Grade DESC
OFFSET 2 FETCH FIRST 1 ROW ONLY

Answer 3

使用ROW_NUMBER窗口功能

;with cte
AS (
SELECT s.Student_Name, g.Grade ,
RN = row_number()over(order by Grade desc)
FROM Student s
 INNER JOIN Grades g on s.Student_ID=g.Student_ID 
)
Select *
From cte
Where RN = 3

选择第三高价值SQLServer

3 个答案: