Question

以下代码旨在为一年中的特定周提取表的记录并汇总数据。除了第0周（2017年12月31日周日是本周的开始），我测试的每个星期的代码运行正常。如果我在phpmyadmin中运行查询，它确实会提供所需的结果。任何人都可以帮助我理解我做错了什么。

try {
            $usid=$_SESSION['uid'];
            $wk = $_GET['wk'];
            $tdy= date("Y-m-d");
            $stmt6 = $db->prepare("
    SELECT 
  YEAR(transaction_date) AS YR,
  COUNT(
    bo_hourly_charges.billing_id_num
  ) AS EVENTS,
  SUM(
    CASE
      WHEN checkout < '16:31:00' 
      THEN 1 
      ELSE 0 
    END
  ) AS early,
  SUM(
    CASE
      WHEN checkout > '16:30:00' 
      THEN 1 
      ELSE 0 
    END
  ) AS late,
  bo_school_enrollment.last_first,
  WEEK(
    bo_hourly_charges.transaction_date
  ) AS wk,
  bo_school_enrollment.student_id,
  bo_school_enrollment.family_id,
  bo_billing_rates.account,
  bo_billing_rates.description,
  bo_school_enrollment.faculty_discount 
FROM
  bo_hourly_charges,
  bo_school_enrollment,
  bo_billing_rates 
WHERE bo_hourly_charges.billing_id_num = bo_school_enrollment.billing_id_num 
  AND billed_by = 'AfterCare' 
  AND bo_hourly_charges.billing_rate_id = bo_billing_rates.billing_rate_id 
  AND WEEK(
    bo_hourly_charges.transaction_date
  ) = :wk 
GROUP BY bo_school_enrollment.faculty_discount,
  bo_school_enrollment.last_first WITH ROLLUP 
           ");
            $stmt6->bindParam(':wk',$wk,PDO::PARAM_STR);
            $stmt6->execute();
             // set the resulting array to associative
            $result6 = $stmt6->setFetchMode(PDO::FETCH_ASSOC); 
            $count6 = $stmt6->rowCount();

Answer 1

我发现了一篇回答我问题的文章。 WEEK功能有多种模式，我需要更改模式以获得所需的结果。 https://www.electricmonk.nl/log/2009/04/13/mysql-week-function-weirdness/

返回零周数据

1 个答案: