Question

我有一个大文本文件，我想将其拆分为几个不同的较小文本文件。也许有人有代码吗？

Original file:
111
222
333
444
555
666

然后将其拆分为3个txt文件

File 1
111
222

File 2
333
444

File 3
555
666

Answer 1

如果您想将原始文件拆分为3个文件，而不拆分行，并将文件分成file_01，file_02和file_03，请尝试以下操作：

split --numeric-suffixes=1 -n l/3 original_file  file_

Answer 2

使用GNU awk：

awk 'NR%2!=0{print >"File " ++c}; NR%2==0{print >"File " c}' original_file

或更短：

awk 'NR%2!=0{++c} {print >"File " c}' file

%是modulo operation

Answer 3

编辑：问题最初要求提供pythonic解决方案。

整个网站都有类似的问题，但这是你的例子的解决方案：

# read ('r') the file ('text.txt'), and split at each line break ('\n')
textFile = open('text.txt','r').read().split('\n')

# setup temporary array as a place holder for the files (stored as strings) to write, 
# and a counter (i) as a pointer
temp = ['']
i = 0

# for each index and element in textfile
for ind,element in enumerate(textFile):
    # add the element to the placeholder
    temp[i] += element+'\n'

    # if the index is odd, and we are not at the end of the text file,
    # create a new string for the next file
    if ind%2 and ind<len(textFile)-1:
        temp.append('')
        i += 1

# go through each index and string of the temporary array
for ind,string in enumerate(temp):
    # write as a .txt file, named 'output'+the index of the array (output0, output1, etc.
    with open('output'+str(ind)+'.txt','w') as output:
        output.write(string)

将大文本文件拆分为较小的文件

3 个答案: