SQL - 将每个值添加到表中的每个其他值

Question

我有一个样本表

table
(2+2)
(2+4)
(2+6)
(4+2)
(4+4)
(4+6)
(6+2)
(6+4)
(6+6)

我想以这种方式将每个值添加到其他每个值：

table
4 
6 
8 
6 
8 
10
8 
10
12

最终结果如下：

lst = [1, 3, 2, 2, 4]

exists = []
total = 0
for nb in lst:
    # if nb is even AND has not been used yet...
    if nb % 2 == 0 and nb not in exists:
        total += nb
        # check the nb as used.
        exists.append(nb)

但我不知道如何以这种方式计算所有值。

Answer 1

自我class ModelName(models.Model): sthree = S3BotoStorage() def file_name(self,filename): ext = filename.split('.')[-1] name = "%s/%s.%s" % ("downloads", uuid.uuid4(), ext) return name upload_file = models.FileField(upload_to=file_name,storage = sthree) def save(self): self.upload_file.storage.headers = {'Content-Disposition': 'attachments; filename="%s"' %self.upload_file.name} super(ModelName, self).save() 获得交叉产品：

CROSS JOIN

如果您需要保证特定订单，请添加select t1.c + t2.c from tablename t1 cross join tablename t2 ：

ORDER BY