Question

我试图从AJAX调用MySQL中检索数据这里是我的代码。

当我从前端调用AJAX时，它将返回null。当我在phpMyAdmin中运行它时，相同的查询将起作用。

这是我的班级文件

    class Bpay{

        private $db;
        private $fm;

        public function __construct(){
            $this->db = new Database();
            $this->fm = new Format();
        }

        public function getAllPaymentRecord($borderid,$month_of,$year_of){

            $border_id  = mysqli_real_escape_string($this->db->link, $borderid);
            $month      = mysqli_real_escape_string($this->db->link, $month_of);
            $year       = mysqli_real_escape_string($this->db->link, $year_of);

            $query = "SELECT * FROM mms_border_payable WHERE border_id = '".$border_id."' AND month_of = '".$month."' AND year_of =  '".$year."' ORDER BY id ASC";
            $result = $this->db->select($query);
            return $result;
        }
    }

这样的处理程序文件。我发送AJAX请求并从类

获取JSON数据的位置

    include 'Bpay.php';

    if(isset( $_POST['borderid'] )) {

        $recordArray = array();

        $regBpay = new Bpay();

        $borderid       = $_POST['borderid'];
        $month_of       = $_POST['month_of'];
        $year_of        = $_POST['year_of'];

        $recordArray['borderid'] = $borderid;
        $recordArray['month_of'] = $month_of;
        $recordArray['year_of'] = $year_of;

        $recordArray['paymentRecords'] = $regBpay->getAllPaymentRecord($borderid,$month_of,$year_of);

        header('Content-Type: application/json');
        echo json_encode($recordArray);
    }

这是我的ajax电话

    var borderid = $("#border").val();
    var month_of = $("#month_of").val();
    var year_of = $("#year_of").val();


    $.ajax({
        url: '../classes/recordHandler.php',
        dataType: "json",
        type: 'POST',
        async: false,
        cache: false,
        data: {
            borderid : borderid,
            month_of : month_of,
            year_of : year_of
        },
        success: function (data) {

            console.log(data);
        },
        error: function (jqXHR, textStatus, errorThrown) {
            console.log(jqXHR);
            console.log(textStatus);
            console.log(errorThrown);
        }
    });

得到了这样的结果

    {
        borderid:"3"
        month_of:"2"
        paymentRecords:
            current_field:null
            field_count:null
            lengths:null
            num_rows:null
            type:null

        year_of:"2018"
    }

我无法理解为什么会这样。提前致谢

Answer 1

谢谢大家。我得到了答案。我试图获取数据没有fetch.now它清楚我。再次感谢。我正在学习php.here是我的代码

public function getAllPaymentRecord($borderid,$month_of,$year_of){

    $border_id  = mysqli_real_escape_string($this->db->link, $borderid);
    $month      = mysqli_real_escape_string($this->db->link, $month_of);
    $year       = mysqli_real_escape_string($this->db->link, $year_of);

    $query = "SELECT * FROM mms_border_payable WHERE border_id = '3' AND month_of = '".$month."' AND year_of =  '".$year."' ORDER BY id ASC";

    $result = $this->db->select($query);
    $resArray = array();

    if($result){
        while($data = $result->fetch_assoc()){
            array_push($resArray, $data);
        }
    }
    return $resArray;
}

MySQL在PHP OOP中的AJAX调用上返回null

1 个答案: