我有点问题。我想在列表中只显示属于添加它的用户的记录。在我的应用中,当我登录时,用户'我想从列表中添加新记录,包括来自ForeignKey的db中的所有记录。如何正确使用?
在' Strona www'当我展开列表时,我会看到所有记录,而不仅仅是用户个人添加的记录。 我的视图是:
@login_required
def new_keyword(request):
if request.method == "POST":
new_keyword = KeywordForm(request.POST)
if new_keyword.is_valid():
new_keyword=new_keyword.save(commit=False)
new_keyword.user = request.user
new_keyword.save()
messages.success(request, 'Pomyślnie dodano słowo kluczowe')
return render(request, 'konto/new_keyword_ok.html')
else:
new_keyword = WebsiteForm()
return render(request, 'konto/new_keyword.html', {'new_keyword':new_keyword})
在 forms.py 我有:
class KeywordForm(forms.ModelForm):
class Meta:
model = Keyword
fields = ('www', 'keyword')
models.py
class Keyword(models.Model):
user = models.ForeignKey(User, on_delete=models.CASCADE, verbose_name="Użytkownik")
www = models.ForeignKey(Website, on_delete=models.CASCADE, verbose_name="Strona www")
keyword = models.CharField(max_length=250, verbose_name="Słowo kluczowe", unique=False)
urls.py
path('new-keyword/', new_keyword, name='new_keyword'),
和 html 用于显示表单:
{% if request.user.is_authenticated %}
<form action="." method="post">
{{ new_keyword.as_p }}
{% csrf_token %}
<p><input type="submit" value="Dodaj nowe słowo kluczowe" ></p>
<a href="{% url 'dashboard' %}">Powrót do monitoringu</a>
</form>
{% endif %}
编辑:
models.py
from django.db import models
from django.contrib.auth.models import User
class Website(models.Model):
user = models.ForeignKey(User, on_delete=models.CASCADE, verbose_name="Użytkownik")
website = models.CharField(max_length=250,verbose_name='Strona www', unique=False)
class Meta:
verbose_name = 'Strona www'
verbose_name_plural = 'Strony www'
def __str__(self):
return self.website
class Keyword(models.Model):
user = models.ForeignKey(User, on_delete=models.CASCADE, verbose_name="Użytkownik")
www = models.ForeignKey(Website, on_delete=models.CASCADE, verbose_name="Strona www")
keyword = models.CharField(max_length=250, verbose_name="Słowo kluczowe", unique=False)
class Meta:
verbose_name = 'Słowo kluczowe'
verbose_name_plural = 'Słowa kluczowe'
def __str__(self):
return self.keyword
答案 0 :(得分:3)
将request.user
传递给您的表单并使用反向关系user.website_set
:
形式:
class KeywordForm(forms.ModelForm):
class Meta:
model = Keyword
fields = ('www', 'keyword')
def __init__(self, user, *args, **kwargs):
super(KeywordForm, self).__init__(*args, **kwargs)
self.fields['www'].queryset = user.website_set.all()
self.user = user
def save(self, commit=True):
instance = super(KeywordForm, self).save(commit=False)
instance.user = self.user
if commit:
instance.save()
return instance
观点:
@login_required
def new_keyword(request):
if request.method == "POST":
new_keyword = KeywordForm(request.user, request.POST)
if new_keyword.is_valid():
new_keyword.save()
messages.success(request, 'Pomyślnie dodano słowo kluczowe')
# DONT DO THIS ! REDIRECT INSTEAD
return render(request, 'konto/new_keyword_ok.html')
else:
new_keyword = KeywordForm(request.user)
return render(request, 'konto/new_keyword.html', {'new_keyword':new_keyword})
作为旁注:成功发布POST you want to redirect后(即使是相同的网址)。当用户重新加载页面时,这可以避免很多麻烦(以及重复提交)
答案 1 :(得分:0)
只需将用户ID传递给您的表单,然后为您的字段设置一个查询集
像这样:如何将用户传递到表单:
在您看来:
@login_required
def new_keyword(request):
if request.method == "POST":
#### Notice this part.
new_keyword = KeywordForm(data=request.POST, u=request.user)
if new_keyword.is_valid():
new_keyword=new_keyword.save(commit=False)
new_keyword.user = request.user
new_keyword.save()
messages.success(request, 'Pomyślnie dodano słowo kluczowe')
return render(request, 'konto/new_keyword_ok.html')
else:
# Notice this part.
new_keyword = WebsiteForm(data=None, u=request.user)
return render(request, 'konto/new_keyword.html', {'new_keyword':new_keyword})
如何在表单中检索用户并设置查询集:
forms.py:
class KeywordForm(forms.ModelForm):
class Meta:
model = Keyword
fields = ('www', 'keyword')
def __init__(self, current_user, *args, **kwargs):
self.u = kwargs.pop("u") ## The user you just passed.
super(KeywordForm, self).__init__(*args, **kwargs)
self.fields['www'].queryset = Website.objects.filter(user=self.u) ## Setting the queryset.