Question

我试图在Python中复制一些Matlab代码，这是我的Matlab代码：

for k = 1:N
    if x(k) > 0.6 %triggers, when Amplitude is above 0.6
       timeOver = ['Abnormal reading detected at Time ', num2str(t(k)), 's. Please change cutting tool !!']; % creating a warning sign to display when abnormality is present
       disp(timeOver) % displaying of warning sign
       h = msgbox(timeOver,'Warning','warn');

       break % 'break' command for stopping of 'for' loop
    end
end

我做了以下替换：

for k = 1:N已更改为for k in numpy.arange(0, N, 1)
if x(k) > 0.6已更改为if x.k > 0.6

我意识到在Matlab中，disp(k)会产生值，而在Python print(k)中会产生0.0

但是，Matlab中的for循环会生成一条消息，而Python不会生成任何内容。

Answer 1

这段代码应解决问题：

import numpy as np

x = np.random.rand(10)  # some values of x; replace it with your values of x
t = np.arange(1, 11) - (np.random.rand(10) - 0.5)  # simulated, not equally spaced timestamps; replace it with your values of t

for idx, val in enumerate(x):
    if val > 0.6:  # triggers, when Amplitude is above 0.6
        print('Abnormal reading detected at Time ' + str(t[idx]) + 's. Please change cutting tool !!')
        break  # 'break' command for stopping of 'for' loop

当幅度超过值时触发消息

1 个答案: