Question

即使Json是正确的，也要获取Gson NumberFormatExcepption

{
    "IsMissCallLogin": true,
    "IsOfficialSurname": true,
    "IsGotraInRegRequest": false,
    "SubCasteLabel": "SubCaste",
    "MissCallWaitSeconds": 7,
    "IsFBAccountKit": true,
    "Status": 1,
    "Message": "Success",
    "Navigation": "KeepSame"
}

使用Gson gradle作为

compile 'com.google.code.gson:gson:2.7'

例外是

NumberFormatException : Thread:main
Exception:com.google.gson.JsonSyntaxException:
java.lang.NumberFormatException: empty String at
com.google.gson.internal.a.s$34.b(Unknown Source) at
com.google.gson.internal.a.s$34.a(Unknown Source) at
com.google.gson.internal.a.k$1.a(Unknown Source) at
com.google.gson.internal.a.l.a(Unknown Source) at
com.google.gson.d.a(Unknown Source) at
com.google.gson.d.a(Unknown Source) at 
com.google.gson.d.a(Unknown Source)

模型类

public class GetUIConfigResponse {
    public boolean IsMissCallLogin;
    public boolean IsOfficialSurname;
    public boolean IsGotraInRegRequest;
    public String SubCasteLabel;
    public int MissCallWaitSeconds;
    public boolean IsFBAccountKit;
    public int Status;
    public String Message;
    public String Navigation;

    public GetUIConfigResponse() {
        IsMissCallLogin = true;
        IsOfficialSurname = true;
        IsGotraInRegRequest = false;
        SubCasteLabel = "SubCaste";

        Status = 0;
        Message = "";
        Navigation = "";
        MissCallWaitSeconds = 5;

        IsFBAccountKit = false;
    }
}

Answer 1

这是你在使用Gson时应该如何制作你的pojo课程。提供的注释很好用，也很方便。

 public class GroupMemberListingResponse {

    @SerializedName("IsMissCallLogin")
    @Expose
    private boolean isMissCallLogin;
    @SerializedName("IsOfficialSurname")
    @Expose
    private boolean isOfficialSurname;
    @SerializedName("IsGotraInRegRequest")
    @Expose
    private boolean isGotraInRegRequest;
    @SerializedName("SubCasteLabel")
    @Expose
    private String subCasteLabel;
    @SerializedName("MissCallWaitSeconds")
    @Expose
    private int missCallWaitSeconds;
    @SerializedName("IsFBAccountKit")
    @Expose
    private boolean isFBAccountKit;
    @SerializedName("Status")
    @Expose
    private int status;
    @SerializedName("Message")
    @Expose
    private String message;
    @SerializedName("Navigation")
    @Expose
    private String navigation;

    public boolean isIsMissCallLogin() {
    return isMissCallLogin;
    }

    public void setIsMissCallLogin(boolean isMissCallLogin) {
    this.isMissCallLogin = isMissCallLogin;
    }

    public boolean isIsOfficialSurname() {
    return isOfficialSurname;
    }

    public void setIsOfficialSurname(boolean isOfficialSurname) {
    this.isOfficialSurname = isOfficialSurname;
    }

    public boolean isIsGotraInRegRequest() {
    return isGotraInRegRequest;
    }

    public void setIsGotraInRegRequest(boolean isGotraInRegRequest) {
    this.isGotraInRegRequest = isGotraInRegRequest;
    }

    public String getSubCasteLabel() {
    return subCasteLabel;
    }

    public void setSubCasteLabel(String subCasteLabel) {
    this.subCasteLabel = subCasteLabel;
    }

    public int getMissCallWaitSeconds() {
    return missCallWaitSeconds;
    }

    public void setMissCallWaitSeconds(int missCallWaitSeconds) {
    this.missCallWaitSeconds = missCallWaitSeconds;
    }

    public boolean isIsFBAccountKit() {
    return isFBAccountKit;
    }

    public void setIsFBAccountKit(boolean isFBAccountKit) {
    this.isFBAccountKit = isFBAccountKit;
    }

    public int getStatus() {
    return status;
    }

    public void setStatus(int status) {
    this.status = status;
    }

    public String getMessage() {
    return message;
    }

    public void setMessage(String message) {
    this.message = message;
    }

    public String getNavigation() {
    return navigation;
    }

    public void setNavigation(String navigation) {
    this.navigation = navigation;
    }

    }

Answer 2

我认为有两种解决方案：

与负责Json的人交谈，并要求他们仔细检查，在所有情况下，他们都会回答给定字段的正确值。我有一段时间没有这个问题，但我收到null而不是整数。这是最简单的解决方案，您不需要做任何代码。此外，此解决方案将修复所有用户的崩溃。

为该类编写自定义解析器。当您使用Gson解析给定的类时，您可以编写一个自定义TypeAdapter，指示Gson如何解析您的Json。我的课程实现如下：

public static class ResponseAdapter extends TypeAdapter<GetUIConfigResponse> {

@Override
public void write(JsonWriter jsonWriter, GetUIConfigResponse response) throws IOException {
    // In case that you need to serialize the class again
    // take a look at http://www.javacreed.com/gson-typeadapter-example/
}

@Override
public GetUIConfigResponse read(JsonReader jsonReader) throws IOException {
    GetUIConfigResponse response = new GetUIConfigResponse();
    jsonReader.beginObject();
    while (jsonReader.hasNext()) {
        switch (jsonReader.nextName()) {
            case "IsMissCallLogin":
                response.setIsMissCallLogin(jsonReader.nextBoolean());
                break;
            case "IsOfficialSurname":
                response.setIsOfficialSurname(jsonReader.nextBoolean());
                break;
            case "IsGotraInRegRequest":
                response.setIsGotraInRegRequest(jsonReader.nextBoolean());
                break;
            case "SubCasteLabel":
                response.setSubCasteLabel(jsonReader.nextString());
                break;
            case "MissCallWaitSeconds":
                String waitString = jsonReader.nextString();
                try {
                    int number = Integer.parseInt(waitString);
                    response.setMissCallWaitSeconds(number);
                } catch (NumberFormatException ex) {
                    // in case of string set the field to a default value
                    response.setMissCallWaitSeconds(5);
                }
                break;
            case "IsFBAccountKit":
                response.setIsFBAccountKit(jsonReader.nextBoolean());
                break;
            case "Status":
                String statusString = jsonReader.nextString();
                try {
                    int number = Integer.parseInt(statusString);
                    response.setStatus(number);
                } catch (NumberFormatException ex) {
                    // in case of string set the field to a default value
                    response.setStatus(0);
                }
                break;
            case "Message":
                response.setMessage(jsonReader.nextString());
                break;
            case "Navigation":
                response.setNavigation(jsonReader.nextString());
                break;
            default:
                jsonReader.skipValue();

        }
    }
    jsonReader.endObject();
    return response;
}
}

然后我像这样解析了Json（我从本地文件读取Json，因此变量inputStreamReader）：

GsonBuilder gsonBuilder = new GsonBuilder();
gsonBuilder.registerTypeAdapter(GetUIConfigResponse.class, new ResponseAdapter());
Gson gson = gsonBuilder.create();
GetUIConfigResponse model =  gson.fromJson(inputStreamReader, GetUIConfigResponse.class);

使用此代码，应该正确解析所有内容，如果整数字段具有字符串值，则将其转换为int（如果可能）。如果无法转换它，那么我设置一些在类的构造函数中找到的默认值。此解决方案的一个优点是它可以防止此类未来的情况（仅适用于这些字段），但如果您的应用程序已经启动，那么您可能会再次发现此次崩溃对于尚未更新应用程序的用户。< / p>

Answer 3

 Gson gson = new GsonBuilder().registerTypeAdapter(Long.class, new LongTypeAdapter()).create();

像

一样使用它

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Android Gson NumberFormatException正确的Json

3 个答案: