Question

students[#]是一个结构数组，students[#].name是结构中的一个字符串，我想确保当用户输入它被验证为字符串的名称时信件。

有人可以告诉我（简单吗？）完成这项工作的方法吗？

我尝试了以下内容无济于事。

        bool checkString(const char *str)
        {
            bool isLetters = true;

            while (*str != '\0')
            {
                if (*str < '65' || *str > '122')
                {
                   //checking to see if it's over or below ASCII alpha characters
                    isLetters = false;
                }

                if (*str < '97' && *str > '90')
                {
                     // checking to see if it's between capital and 
                     //lowercase alpha char's
                    isLetters = false;
                }

                ++str;
            }

            return isLetters;
        }

        main
        {
        //...
                for (int i = 0; i < numStudents; ++i)
                {
                    valid = true;
                    do
                    {
                        valid = true;
                        cout << "Enter NAME for student #" << i + 1 << ":" << endl;
                        cin >> students[i].name;
                        if (cin.fail() || !checkString(students[i].name.c_str()))
                            // tried to see if i could convert it to a c-style 
                            //string to check char by char
                        {
                            cin.clear();
                            cin.ignore();
                            cout << "Please enter a valid input." << endl;
                            valid = false;
                        }
                    } while (!valid);
        //...
        return 0;
        }

        `

Answer 1

ASCII码是整数，不要用引号括起来。

bool checkString(const char *str)
{
    bool isLetters = true;
    while (*str != '\0')
    {
        if (*str < 65 || *str > 122)
        {
           //checking to see if it's over or below ASCII alpha characters
            isLetters = false;
        }

        if (*str < 97 && *str > 90)
        {
             // checking to see if it's between capital and 
             //lowercase alpha char's
            isLetters = false;
        }
        ++str;
    }
    return isLetters;
}

你仍然在努力，功能isalpha是专为此任务而设计的

#include <cctype>

bool checkString(const char *str)
{
    bool isLetters = true;
    while (*str != '\0')
    {
        if (!isalpha(*str)))
            isLetters = false;
        ++str;
    }
    return isLetters;
}

然后当你意识到这不是一封信，没有点进行检查时，你可以马上回来

#include <cctype>

bool checkString(const char *str)
{
    while (*str != '\0')
    {
        if (!isalpha(*str)))
            return false;
        ++str;
    }
    return true;
}

Answer 2

您必须使用ascii值检查每个字符是否为字母。

bool checkString(string stdunt)
    {
        bool isLetters = true;
        for (int i = 0; i < stdunt.length(); i++)
            {
                    if (stdunt[i] < 65 || stdunt[i] > 122)
                    { return false; }

                    if (stdunt[i] < 97 && stdunt[i] > 90)
                    { return false; }
            }
        return isLetters;
    }

int main()
{

int numStudents=5;
string students[numStudents];
    for (int i = 0; i < numStudents; i++)
    {
        bool valid = true;


    do{
            valid = true;
            cout << "Enter NAME for student #" << i + 1 << ":" << endl;
            cin >> students[i];
//            cout <<students[i];
            if (cin.fail() || !checkString(students[i]))
            {
                cin.clear();
                cin.ignore();
                cout << "Please enter a valid input." << endl;
                valid = false;
            }
      } while (!valid);
    }
    cout << "Complete";
    return 0;
}
`

如何验证用户输入的字符串到std :: cin？

2 个答案: