我尝试使用正则表达式来表示bash if语句。
if [[ "$@" =~ blah blah ]]; then … ; fi
`result expected:
-a (not match: as standalone)
-auto (not match: as standalone)
-lv (not match: no "a" or "--auto")
-l --verbose (not match: no "a" or "--auto")
-v --log (not match: no "a" or "--auto")
-n --make-auto (not match: no "a" or "--auto")
-g --auto-gen (not match: no "a" or "--auto")
-a -l (match: "-a" used with other)
-l -a -v (match: "-a" used with other)
-l -s -a (match: "-a" used with other)
-ls -a (match: "-a" used with other)
-va -s (match: "-a" used with other)
-lav (match: a used with other)
-alva (match: a used with other)
-l --auto (match: "--auto" used with other)
-l --auto (match: "--auto" used with other)
--auto -lv (match: "--auto" used with other)
--auto --log (match: "--auto" used with other)
--auto --log (match: "--auto" used with other)`
我做了很多测试，我认为我对正则表达式一无所知 我已经阅读了很多教程和链接，但是如果我理解的话，那里没有AND但只有OR
`(^[^--auto]$|[[:space:]]--auto[[:space:]]{0,}|^--auto[[:space:]]{1,}[[:graph:]]{1,})
"--log --auto" => OK
"--log --auto --verbose" => OK
"--log --auto-gen" => KO match but need to not match no --auto`
`(^[^--auto]$|[[:space:]]--auto[[:space:]]{1,}|^--auto[[:space:]]{1,}[[:graph:]]{1,})
"--log --auto --verbose" => OK
"--log --verbose --auto" -> KO`
`(^[^--auto]$|[[:space:]]--auto[[:space:]]{1,}$|^--auto[[:space:]]{1,}[[:graph:]]{1,})`
依旧......
现在有了简短的参数......即使“-a”一个人也匹配任何东西！
`((^-([a-z0-9])*a{1,}.*)|([[:space:]]-([a-z0-9])*a{1,}.*))
"-a" => KO match and do not need
"-l -a" => OK
"-a -l" => OK
"-la" => OK
"-lv" => OK
"-a -l -v" => OK
"-v -z -a" => OK`
如果我在前面添加(^-[^a]$) ...没效果
`(^-[^a]$)|((^-([a-z0-9])*a{1,}.*)|([[:space:]]-([a-z0-9])*a{1,}.*))`
如果我混合短而长的badaboum！
我可能会通过分别测试params来解决这个问题，但我正在尝试测试整条线路。
是否可以在正则表达式和bash中执行此操作？
提前感谢您的建议和帮助。