Question

我正在尝试添加两个多项式，但每当我的代码执行时它返回零。我希望有人可以向我指出我正在做什么以及如何解决它。感谢

{
  "Comment": "A state machine that publishes to SNS after a deployment completes.",
  "StartAt": "StartDeployment",
  "States": {
    "StartDeployment": {
      "Type": "Task",
      "Resource": "arn:aws:lambda:us-east-1:012345678912:function:KickOffDeployment",
      "ResultPath": "$.guid",
      "Next": "CheckIfDeploymentComplete"
    },
    "CheckIfDeploymentComplete": {
      "Type": "Task",
      "Resource": "arn:aws:lambda:us-east-1:012345678912:function:CheckIfDeploymentComplete",
      "Next": "TriggerWebAppRefresh",
      "InputPath": "$.guid",
      "ResultPath": "$.status",
      "Retry": [ {
         "ErrorEquals": [ "INPROGRESS" ],
         "IntervalSeconds": 5,
         "MaxAttempts": 240,
         "BackoffRate": 1.0
       } ],
       "Catch": [ {
            "ErrorEquals": ["FAILED"],
            "Next": "DeploymentFailed"
       }]
    },
    "DeploymentFailed": {
      "Type": "Fail",
      "Cause": "Deployment failed",
      "Error": "Deployment FAILED"
    },
    "TriggerWebAppRefresh": {
      "Type": "Task",
      "Resource": "arn:aws:lambda:us-east-1:012345678912:function:SendSNSToWebapp",
      "InputPath": "$.guid",
      "End": true
    }
  }
}

Answer 1

您正在尝试将链接列表poly1和poly2添加到一起，结果将存储在新的链接列表中。

但是，您没有正确构建生成的链接列表。在为每个不同程度创建新节点时，您无法正确创建新节点，并将它们链接在一起。代码：

polyAdd = new Node (coeff, degree, null);

删除对前一个polyAdd的任何引用。

保持链表顺利的正确方法是：

polyAdd.next = new Node(coeff, degree, null);

使用链接列表添加多项式Java

1 个答案: