Question

我收到错误没有运算符“=”匹配这些操作数操作数类型是std :: basic_ostream＆gt;在C ++中运行代码时是int，我不确定是什么导致错误。

#include <iostream>
#include <string>
#include <fstream>
#include <cctype>
using namespace std;

int main()
{
    int num1, num2;
    double average;

    // Input 2 integers
    cout << "Enter two integers separated by one or more spaces: ";
    cin >> num1, num2;

    //Find and display their average
    cout << average = (num1 + num2) / 2;

    cout << "\nThe average of these 2 numbers is " << average << "endl";

    return 0;
}

Answer 1

编译器处理

cout << average = (num1 + num2) / 2;

如：

(cout << average) = ((num1 + num2) / 2);

有关详细信息，请参阅C++ operator precedence。

修正：

cout << (average = (num1 + num2) / 2);

更喜欢简单的陈述：

average = (num1 + num2) / 2;
cout << average;

另外

cin >> num1, num2;

应该是

cin >> num1 >> num2;

没有运算符“=”匹配这些操作数操作数类型是std :: basic_ostream <char，std :: char_traits <char =“”>＆gt; = int

1 个答案: