显示来自其他网页的新闻

时间:2011-02-01 15:13:13

标签: php cross-domain

我想将来自anoter网页的新闻显示在我的网页上,我无法找到最佳方法。

其他网页上的新闻显示在div类中,如下所示

<div class="news-container"> 
<div class="news-list"><a href="news/1/" title="abcd"><img src="abcd.jpg" /><strong>abcd</strong></a> 
    <p>What you see is what you get. <span class="morelink"><a href="news/1/" title="abcd">Read more</a></span></p> 
    <div class="clear-both"></div> 
</div> 
<div class="news-list"><a href="news/2/" title="efgh"><img src="efgh.jpg" /><strong>efgh</strong></a> 
    <p>What you see is what you get. <span class="morelink"><a href="news/3/" title="abcd">Read more</a></span></p> 
    <div class="clear-both"></div> 
</div> 
<div class="news-list"><a href="news/3/" title="ijkl"><img src="ijkl.jpg" /><strong>ijkl</strong></a> 
    <p>What you see is what you get. <span class="morelink"><a href="news/3/" title="abcd">Read more</a></span></p> 
    <div class="clear-both"></div> 
</div> 
<div class="news-list"><a href="news/4/" title="mnop"><img src="mnop.jpg" /><strong>mnop</strong></a> 
    <p>What you see is what you get. <span class="morelink"><a href="news/4/" title="abcd">Read more</a></span></p> 
    <div class="clear-both"></div> 
</div>

我希望能够浏览新闻并将其显示在我自己的页面上,并根据我们自己的网站布局重新排列。

<div class="other-news"> 
<div class="news-list"><strong>abcd</strong>
    <p>What you see is what you get. <a href="news/1/" title="abcd"><img src="abcd.jpg" /></a></p> 
</div> 
<div class="news-list"><strong>efgh</strong>
    <p>What you see is what you get. <a href="news/3/" title="abcd"><img src="efgh.jpg" /></a> </p> 
</div> 
<div class="news-list"><strong>ijkl</strong>
    <p>What you see is what you get. <a href="news/3/" title="abcd"><img src="ijkl.jpg" /></a> </p> 
</div> 
<div class="news-list"><strong>mnop</strong>
    <p>What you see is what you get. <a href="news/4/" title="abcd"><img src="mnop.jpg" /></a> </p>
</div>

所有建议都非常受欢迎。

// Nyborg

1 个答案:

答案 0 :(得分:1)

您需要查看PHP cURL或file_get_contents(安全问题)或查看PHP HTML DOM Parser。

还要看看你做什么的合法性? (如果他们想让你有内容,他们通常会提供API)