Question

尝试在数据库中插入数据。数据没有存储，我不知道这里有什么问题。

这些是要打印的错误按摩代码

        System.out.println(e.getErrorCode());
        System.out.println(e.getSQLState());
        System.out.println(e.getMessage());
        System.out.println(e.getCause());
        System.out.println(e.getNextException());

控制台中的

错误

Connection to SQLite has been established.
0
null
null
null
null

添加课程以便于详细了解。

CompanyDetailsController.java

    @FXML
private void saveCompanyDetails(ActionEvent event) throws IOException {

    String companyName = CompanyNameField.getText();
    String details = detailsField.getText();
    String address = addressField.getText();
    String country = countryField.getValue().toString();
    String city = cityField.getValue().toString();
    String state = stateField.getValue().toString();
    String stateCode = stateCodeField.getValue().toString();
    String pin = pinField.getText();
    String contactNumber = contactField.getText();
    String email = emailField.getText();
    String website = websiteField.getText();
    String gstin = gstinField.getText();
    String pan = panField.getText();
    String tan = tanField.getText();
    String taxtation = textationField.getValue().toString();
    String taxRate = taxRateField.getText();
    String proprietor = proprietorField.getText();
    String aadhaar = aadhaarField.getText();
    String currency = currencyField.getText();
    String companyCode = companyCodeField.getText();
    String pos = posField.getText();

    fis= new FileInputStream(file);

    String sql = "INSERT INTO companyDetails (companyName, additionalDetails, address, country, city, state, stateCode, pinCode, contactNumber,"
            + "email, website,GSTIN, TAN,PAN, taxationType, taxRate, proprietor,adhaarNo,currency,companyCode,POScode,logo,cid) VALUES(?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)";

    try {

        PreparedStatement pstmt = con.prepareStatement(sql);
        pstmt.setString(1, companyName);
        pstmt.setString(2, details);
        pstmt.setString(3, address);
        pstmt.setString(4, country);
        pstmt.setString(5, city);
        pstmt.setString(6, state);
        pstmt.setString(7, stateCode);
        pstmt.setString(8, pin);
        pstmt.setString(9, contactNumber);
        pstmt.setString(10, email);
        pstmt.setString(11, website);
        pstmt.setString(12, gstin);
        pstmt.setString(13, tan);
        pstmt.setString(14, pan);
        pstmt.setString(15, taxtation);
        pstmt.setString(16, taxRate);
        pstmt.setString(17, proprietor);
        pstmt.setString(18, aadhaar);
        pstmt.setString(19, currency);
        pstmt.setString(20, companyCode);
        pstmt.setString(21, pos);
        pstmt.setBinaryStream(22,fis);


        pstmt.executeUpdate();

        hf.showDialog("Company Details Added Successfully");
    } catch (SQLException e) {

        System.out.println(e.getErrorCode());
        System.out.println(e.getSQLState());
        System.out.println(e.getMessage());
        System.out.println(e.getCause());
        System.out.println(e.getNextException());
    }
}

任何人都可以帮忙吗？

Answer 1

您可以在github中找到JDBC v4，包括一些特殊的setter，如BLOB，Binaries类型......，不支持

public void setBinaryStream(int parameterIndex, InputStream x, long length)
        throws SQLException {
    // TODO Support this
    throw new SQLFeatureNotSupportedException();
}

对于日志中遇到的问题，它使用的SQLFeatureNotSupportedException构造函数没有参数。医生说：

构造一个SQLFeatureNotSupportedException对象。 原因是，SQLState初始化为null，供应商代码初始化为0 。原因未初始化，随后可以通过调用Throwable.initCause（java.lang.Throwable）方法进行初始化。

org.sqlite.jdbc4.JDBC4PreparedStatement.setBinaryStream中的java.sql.SQLFeatureNotSupportedException（JDBC4PreparedStatement.java:96）

1 个答案: