我正在尝试使用地理位置api来获取该位置的纬度和经度。因此,我在开发人员控制台上创建了一个项目并创建了一个api密钥。我在api https://www.googleapis.com/geolocation/v1/geolocate?key=YOUR_API_KEY
中使用了这个api密钥所以当我在邮差中执行请求时,它运行良好。 但是,当我尝试在应用程序中执行相同的请求时,它会将响应作为响应代码400.
根据开发人员指南的响应代码400
https://developers.google.com/maps/documentation/geolocation/intro#errors
显示api键错误时出现。但是密钥如何在邮递员中而不是在应用程序中工作?
以下是服务器请求的代码:
public JSONObject sendPostRequest1(String data) {
try {
URL url = new URL(api);
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setRequestMethod("POST");
// con.setRequestProperty("content-type", "application/x-www-form-urlencoded");
con.setDoOutput(true);
con.setDoInput(true);
OutputStreamWriter writer = new OutputStreamWriter(con.getOutputStream());
try {
writer.write(data);
} catch (Exception e) {
Log.e("Exception111", e.toString());
}
writer.close();
int responseCode = con.getResponseCode();
if (responseCode == HttpURLConnection.HTTP_OK || responseCode == HttpURLConnection.HTTP_CREATED) {
StringBuilder sb = new StringBuilder();
BufferedReader reader = new BufferedReader(new InputStreamReader(con.getInputStream()));
String line = "";
while ((line = reader.readLine()) != null) {
sb.append(line);
}
reader.close();
Log.d("ServerResponse", new String(sb));
String output = new String(sb);
return new JSONObject(output);
} else {
Log.e("Exception", "" + responseCode);
}
}
catch (JSONException je)
{
je.printStackTrace();
return Excpetion2JSON.getJSON(je);
}
catch(IOException e)
{
}
return null;
}
异步任务:
public class GetLocationAsyncTask extends AsyncTask<String, Void, JSONObject> {
String api;
JSONObject jsonParams;
Context mContext;
private ProgressDialog loadingDialog;
private String number,code;
public GetLocationsCallBack getLocationsCallBack;
public GetLocationAsyncTask(Context context,GetLocationsCallBack getLocationsCallBack) {
this.mContext = context;
this.getLocationsCallBack = getLocationsCallBack;
}
public interface GetLocationsCallBack {
void doPostExecute(ArrayList<Location> list);
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected JSONObject doInBackground(String... params) {
try {
api = "https://www.googleapis.com/geolocation/v1/geolocate?key=AIzaSyCArRAX4oHdfFWrTWhXrOVBQtbs";
jsonParams = new JSONObject();
jsonParams.put("cellId", params[0]);
jsonParams.put("locationAreaCode",params[1]);
ServerRequest request = new ServerRequest(api, jsonParams);
return request.sendPostRequest1(jsonParams.toString());
} catch (Exception ue) {
return Excpetion2JSON.getJSON(ue);
}
} //end of doInBackground
@Override
protected void onPostExecute(JSONObject response) {
super.onPostExecute(response);
if(response.has("location"))
{
try {
Location location = new Location();
location.setLattitude(response.getString("lat"));
location.setLongitude(response.getString("lng"));
ArrayList<Location> locations = location.getLocationArrayList();
locations.add(location);
}
catch (JSONException je)
{
Log.d("JsonException",je.toString());
}
}
if (loadingDialog.isShowing())
loadingDialog.dismiss();
}
}
执行异步任务:
TelephonyManager telephonyManager = (TelephonyManager)getSystemService(Context.TELEPHONY_SERVICE);
GsmCellLocation cellLocation = (GsmCellLocation)telephonyManager.getCellLocation();
int cellid= cellLocation.getCid();
int celllac = cellLocation.getLac();
Log.d("CellLocation", cellLocation.toString());
Log.d("GSM CELL ID", String.valueOf(cellid));
Log.d("GSM Location Code", String.valueOf(celllac));
GetLocationAsyncTask getLocationAsyncTask = new GetLocationAsyncTask(MainActivity.this,MainActivity.this);
getLocationAsyncTask.execute(String.valueOf(cellid),String.valueOf(celllac));
这有什么问题吗?请帮忙。谢谢..
答案 0 :(得分:1)
你必须告诉接收方你发送的是json
con.setRequestProperty("Content-Type", "application/json; charset=UTF-8");