如何在Java中拆分期间忽略所需的字符串？

Question

我有一个像

这样的字符串

pchase_history:array<struct<pchase_channel:string,trans_dt:string,sku_id:string,sold_qty:bigint>>,first_pchase_dt:string,last_pchase_dt:string,trans_cnt:bigint,last_pchase_sku_cnt:bigint,no_of_pchase_days:bigint,lst_pchase_channel:array<struct<pchase_channel:string>>

我需要将其拆分为＆＃39;，＆＃39;但不想分裂（结构数组）array<struct<pchase_channel:string,trans_dt:string,sku_id:string,sold_qty:bigint>>
我希望split方法忽略这些struct数组并拆分其余的字符串。

我如何通过拆分方法实现这一目标？

任何帮助都将不胜感激。

Answer 1

您可以使用正则表达式替换之前的struct 数组，如下所示进行拆分：

String value = "pchase_history:array<struct<pchase_channel:string,trans_dt:string,sku_id:string,sold_qty:bigint>>,first_pchase_dt:string,last_pchase_dt:string,trans_cnt:bigint,last_pchase_sku_cnt:bigint,no_of_pchase_days:bigint,lst_pchase_channel:array<struct<pchase_channel:string>>";

value = value.replaceAll("(array<struct<.*?>>)", "array");
String[] splitedValues = value.split(",");

System.out.println(Arrays.toString(splitedValues));

输出：

[pchase_history:array, first_pchase_dt:string, last_pchase_dt:string, trans_cnt:bigint, last_pchase_sku_cnt:bigint, no_of_pchase_days:bigint, lst_pchase_channel:array]

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