我的排序应该按国家/地区排序 - “India”始终位于顶部,其余按字母排序。
如何使用 mongo-shell命令实现这一目标?
{
"_id" : ObjectId("5a797000287389c34c70c525"),
"Country" : "World",
"Population" : "7550262101"
}
{
"_id" : ObjectId("5a797000287389c34c70c526"),
"Country" : "China",
"Population" : 1409517397
}
{
"_id" : ObjectId("5a797000287389c34c70c527"),
"Country" : "India",
"Population" : 1339180127
}
{
"_id" : ObjectId("5a797000287389c34c70c528"),
"Country" : "USA",
"Population" : 324459463
}
{
"_id" : ObjectId("5a797000287389c34c70c529"),
"Country" : "Indonesia",
"Population" : 263991379
}
答案 0 :(得分:-1)
在参考Dynamic Sticky Sorting in Mongo for a simple value or list上的另一篇文章后,我找到了达到预期效果的方法
db.population.aggregate(
[
{$project: {
Country: 1,
Population: 1,
sticky: {$cond: [{$eq: ['$Country', 'India']}, 1, 0]}
}},
{$sort:
{sticky: -1,
Country: 1}
},
{$project: {
Country: 1,
Population: 1,
}}
])
上述查询的结果是
{ "_id" : ObjectId("5a797000287389c34c70c527"), "Country" : "India", "Population" : 1339180127 }
{ "_id" : ObjectId("5a797000287389c34c70c525"), "Country" : "World", "Population" : "7550262101" }
{ "_id" : ObjectId("5a797000287389c34c70c526"), "Country" : "China", "Population" : 1409517397 }
{ "_id" : ObjectId("5a797000287389c34c70c528"), "Country" : "USA", "Population" : 324459463 }
{ "_id" : ObjectId("5a797000287389c34c70c529"), "Country" : "Indonesia", "Population" : 263991379 }