Question

我有两年的静态数据。我的列名为stats_date，P2P_volume。最初我在oracle sql developer中创建了以下查询单日

选择＆＃39; 1＆＃39;作为KPI_ID，＆＃39; P2P＆＃39;作为KPI_DESC，＆＃39; 22-MAR-17＆＃39;作为日期， （总和（在add_months之间的STATS_DATE时的情况（＆＃39; 22-MAR-17＆＃39;，0）-13 和add_months（＆＃39; 22-MAR-17＆＃39;，0）-7然后P2P_VOLUME其他0结束）） LAST_WEEK_Volume，

  (sum(case when STATS_DATE between add_months('22-MAR-17',0)-6
and add_months('22-MAR-17',0)  then P2P_VOLUME else 0 end )) THIS_WEEK_Volume from table

我的问题是我想要创建动态查询，它会给我Last_week_volume，而this_week_volume日期明智两年。而不是单日

Answer 1

在没有完整的样本数据和要求的情况下，我的假设是：

每个KPI每天有一行
可以满足current week，previous week的定义使用'IW'日期格式掩码

此解决方案使用子查询来计算每周度量的总和。这将输入主查询，该查询使用分析lag()函数来显示当前周和前一周的总计。

with cte as (
  select kpi
        , to_char(static_date, 'YYYY') as yr
       , to_char(static_date, 'IW') as wk
       , sum(volume) as wk_volume
       , sum(value) as wk_value
       , sum(revenue) as wk_revenue
  from t23
  group by kpi,to_char(static_date, 'YYYY'), to_char(static_date, 'IW')
)
select kpi
       , yr||'-'||wk as year_wk
       , wk_volume as curr_wk_volume
       , lag(wk_volume) over (order by yr, wk) as prev_wk_volume
       , wk_value as curr_wk_value
       , lag(wk_value) over (order by yr, wk) as prev_wk_value
       , wk_revenue as curr_wk_revenue
       , lag(wk_revenue) over (order by yr, wk) as prev_wk_revenue
from cte
order by 1, 2
/

有a SQL Fiddle demo here。

oracle sql中的日级计算

1 个答案: