Question

python newbie：

json1.json

{
    "key1": {
        "s11": 1,
        "s12": 2,
        "s13": "abc"
    },

    "key2": {
        "s21": [1, 2, 3, 4],
        "s22": {
            "s221": {
                "s2211": "abc"
            }
        }
    },
    "key3": "name1"
}

json2.json

{
    "key1": {
        "p12": 2,
        "p13": "abc",
        "s11": 1
    },

    "key2": {
        "ps22": {
          "ps221": {
            "ps2211": "abc"
          }
        },
        "ps21": ["1", "2", "3", "4"],
        "ps23" : "abc",
        "ps24":1,
        "s21": [1,2,3,4]
    }
}

我试图比较两个json对象名称; json1.json和json2.json并希望列出对象名称的差异例如，列出以下差异
1. json1中存在json2缺少key3 - ＆gt;用下面的代码得到这个 2. key2.s22更改为key2.ps22，key1.s12更改为key1.p12
3.不会打扰与key2.ps22.ps221.ps2211不同的key2.s22.s221.s2211，因为想捕获初始的层次差异

有人可以帮助我使用适当的方法或命令来捕捉这些差异吗？

我可以通过以下代码获取对象名称的差异。

d1=json.load(open("json1.json"))
d2=json.load(open("json2.json"))
s1=set(d1.keys()) - set(d2.keys())
print(s1)

o / p - ＆gt; { 'KEY3'}

但我的要求是在下一级层次结构中获得差异，即， key2.s22更改为key2.ps22
key2.s21更改为key2.ps21

Answer 1

import json

d1=json.load(open("1.json"))
d2=json.load(open("2.json"))

d11=list(d1.keys())
d22=list(d2.keys())

print(set(d1.keys())^set(d2.keys()))
chk_list = ["key2"]  # picking the keys to get the assymetry keynmaes within keynames

for i in chk_list:
    print(sorted(list(d1[i].keys())))
    print(sorted(list(d2[i].keys())))
    print(set(d1[i].keys()) ^ set(d2[i].keys()))

输出

{'key3'}
['s21', 's22']
['ps21', 'ps22', 'ps23', 'ps24', 's21']
{'ps23', 's22', 'ps24', 'ps22', 'ps21'}

Python：获取jsons之间对象名称和子对象的差异列表

1 个答案: