Question

如何迭代pandas数据框中字典列表的字典，其中一列是Response。

Response = {"query":"hi","intents":[{"intent":"greeting","score":0.941468239},{"intent":"sentinel","score":7.298465E-06},{"intent":"analyticsPage","score":3.77489937E-06},{"intent":"KaaraServices","score":0.0251461584},{"intent":"goodBye","score":0.357869864},{"intent":"servicesPage","score":2.3839857E-05},{"intent":"PredAnalytics","score":3.21742641E-06},{"intent":"ykaara","score":0.006888155},{"intent":"creator","score":0.061054837}],"entities":[]},

我想获得最高分的意图。

Answer 1

您可以将'intents'的值（dicts列表）转换为DataFrame，然后使用argmax：

df = pd.DataFrame(Response["intents"])

它的输出是：

          intent     score
0       greeting  0.941468
1       sentinel  0.000007
2  analyticsPage  0.000004
3  KaaraServices  0.025146
4        goodBye  0.357870
5   servicesPage  0.000024
6  PredAnalytics  0.000003
7         ykaara  0.006888
8        creator  0.061055

然后是最大值：

df.iloc[df['score'].argmax(),:]

这将返回：

intent    greeting
score     0.941468
Name: 0, dtype: object

Answer 2

我确定还有特定的pandas方法，但另一个选择是提取字典并将其排序为通用字典。

from operator import itemgetter

# Get pandas frame from somewhere
response = getresponse()

# Convert list of dictionary to dictionary
d = {}
for item in response["intents"]:
    d[item["intent"]] = item["score"]

# Sort dictionary, get highest scoring element
sorted(d.items(), key=itemgetter(1), reverse=True)[0]

Answer 3

试试这个： -

Response = {"query":"hi","intents":[{"intent":"greeting","score":0.941468239},{"intent":"sentinel","score":7.298465E-06},\
{"intent":"analyticsPage","score":3.77489937E-06},{"intent":"KaaraServices","score":0.0251461584},\
{"intent":"goodBye","score":0.357869864},{"intent":"servicesPage","score":2.3839857E-05},\
{"intent":"PredAnalytics","score":3.21742641E-06},{"intent":"ykaara","score":0.006888155},\
{"intent":"creator","score":0.061054837}],"entities":[]},
max_score = []
for i in Response:
    for j in i['intents']:
        max_score.append(j['score'])
print(max(max_score)) #your expected outpu

迭代pandas数据帧中字典列表的字典

3 个答案: