我正在运行此命令：
AWS_PROFILE=sandbox aws s3 cp local_path bucket --recursive
这很好用。我想运行一个python脚本。这是我的代码：
cmd = ['AWS_PROFILE=sandbox', 'aws', 's3', 'cp', local_path, bucket, '--recursive']
subprocess.Popen(cmd).communicate()
并且它不起作用。
错误追溯：
File "bin/run_report.py", line 128, in main
subprocess.Popen(cmd).communicate()
File "/usr/local/Cellar/python/2.7.14/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 390, in __init__
errread, errwrite)
File "/usr/local/Cellar/python/2.7.14/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 1025, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
我不明白我做错了什么。我已经三次检查了本地和存储桶的路径，如上所述，它可以从shell运行（我不想运行shell = True）
答案 0 :(得分：1)
使用<?php
session_start();
if(!isset($_SESSION['u_uid'])){
header("Location: http://motoko.sorainsurance.com.au");
}
$uid = $_SESSION['u_id'];
require_once('connect.php');
$ReadSql = "SELECT * FROM `contact` WHERE users_id=$uid ORDER BY Name";
$res = mysqli_query($connection, $ReadSql);
?>
<!DOCTYPE html>
<html>
<head>
<title>Motoko</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js">
</script>
</head>
<body>
<div class="container">
<div class="row">
<table class="table">
<tr>
<th>
<strong>Extras</strong>
</th>
</tr>
<?php while($r = mysqli_fetch_assoc($res)){ ?>
<tr>
<td>
<a href="update.php?id=<?php echo $r['id'] ?>">Edit</a>
</td>
<td>
<input type="button" onClick="deleteme('<?php echo $r['u_uid']; ?>')" name="Delete" value="Delete">
</td>
</tr>
<?php } ?>
</table>
</div>
</body>
</html>
<script language="Javascript">
function deleteme(delid){
if(confirm("Are you sure you want to Delete?")){
window.location.href='delete.php?del_id=delid';
}
}
</script>
cli aws开关选择个人资料。
--profile该命令现在应为：
cmd = ['aws', '--profile=sandbox', 's3', 'cp', '--recursive', local_path, bucket]
print(' '.join(cmd))
subprocess.Popen(cmd).communicate()