在运行时使用Serialize.Linq编译表达式

时间:2018-02-06 00:17:03

标签: c# linq serialization expression func

我正在尝试序列化和反序列化Linq查询。目前我正在使用Serialize.Linq通过json序列化和反序列化Linq查询。像这样:

    public async Task StoreQuery<T>(string queriedTypeName, string queryName, Expression<Func<T, bool>> query, IEnumerable<T> results)
        where T : class, IStorable
    {

        var expressionSerializer = new ExpressionSerializer(new Serialize.Linq.Serializers.JsonSerializer());
        var queryJson = expressionSerializer.SerializeText(query);

        await storage.AddQuery(queriedTypeName + ".queries", queryJson, ...);
        //etc...
    }

如果我知道查询表达式的操作类型,我能够成功反序列化查询:

    public static bool QueryWouldContain<T>(T storable, string queryJson)
        where T : class, IStorable
    {
            var queryStatement = expressionSerializer.DeserializeText(queryJson);
        var expressionType = queryStatement.ToExpressionNode().ToExpression<Func<T,bool>>().Compile();

        var objectBelongsInQueryResults = expressionType.Invoke(obj)
        return objectBelongsInQueryResults;
    }

但是,我希望能够在运行时检测该类型,而不是在这种情况下编译时间:

    public static async bool QueriesWouldContain<T>(IEnumerable<T> storables, List<string> queryStrings)
        where T : class, IStorable
    {

        foreach (var querystring in queryStrings)
        {
            var expressionSerializer = new ExpressionSerializer(new JsonSerializer());
            var queryStatement = expressionSerializer.DeserializeText(querystring);

            var expression = queryStatement.ToExpressionNode().ToExpression<Func<?, bool>>().Compile();

            foreach (var storable in storables)
            {
                if (isOfTypeMatchingQuery(storable, expression))
                {
                    var result = expression.Invoke(storable);

                    if (result == false)
                    {
                        return false;
                    }
                }
            }
            return true;
        }

有没有办法从表达式中获取正在操作的类型?如果是这样,有没有办法将该表达式转换为Func?

2 个答案:

答案 0 :(得分:4)

调用ToExpression时,您不必指定通用类型。只需测试,如果它返回LambdaExpression

public static async bool QueriesWouldContain<T>(IEnumerable<T> storables, List<string> queryStrings)
    where T : class, IStorable
{

    foreach (var querystring in queryStrings)
    {
        var expressionSerializer = new ExpressionSerializer(new JsonSerializer());
        var queryStatement = expressionSerializer.DeserializeText(querystring);

        var expression = queryStatement.ToExpressionNode().ToExpression();
        if (!(expression is LambdaExpression lambdaExpression))
            continue; // TODO: or throw
        var d = lambdaExpression.Compile();
        foreach (var storable in storables)
        {
            if (isOfTypeMatchingQuery(storable, d))
            {
                var result = (bool)d.Invoke(storable);

                if (result == false)
                {
                    return false;
                }
            }
        }
        return true;
    }
}

答案 1 :(得分:2)

在@esskar发布他的回答之前,我想出了这个丑陋的话:

...
var expressionNode = queryStatement.ToExpressionNode();
var funcType = typeof(Func<,>).MakeGenericType(new Type[] { type, typeof(bool) });
var method = typeof(ExpressionNode).GetMethods().First(meth => meth.GetGenericArguments().Any() && meth.Name == "ToExpression" && meth.GetParameters().Count() == 1);
var methodWithGenerics = method.MakeGenericMethod(funcType);
dynamic expressionUncompiled = methodWithGenerics.Invoke(expressionNode, new object[] { null });
var expression = expressionUncompiled.Compile();
不用说,他的回答更为可取。