Question

我目前正在开展一个学校项目，并且无法使用此功能。在我的代码中，用户应该能够在textarea中插入他们的名字和/或电子邮件，当他们按下更新按钮时，应该在MySql数据库中更新信息。为了理解代码我做了两个if语句来检查值“updateUser”文件获取是否为空。

我的选择代码：

<?php
include('connection.php');
session_start();

if($_SERVER["REQUEST_METHOD"] == "POST") {
$firstname = mysqli_real_escape_string($conn,$_POST["firstname"]);
$email = mysqli_real_escape_string($conn,$_POST["email"]);

$sql = "SELECT * FROM employee where username ='$username'";

if($result = mysqli_query($conn, $sql)){
    if(mysqli_num_rows($result) > 0){ //kollar/retunerar rows i result set
        echo "<table>"; //tabellen
        echo "<table border=1";
            echo "<tr>";
                echo "<th>firstname</th>";
                echo "<th>email</th>";
            echo "</tr>";
        while($row = mysqli_fetch_array($result)){ //Fetch a result row as an array

            echo "<tr>";
            echo '<form class="" action="updateEmployee.php" method="post">'; 
                echo "<textarea >" . $row['firstname'] . "</textarea>";
                echo "<textarea>" . $row['email'] . "</textarea>";
                echo '<input type="submit" name="updateEmp" value="uppdatera">'; 
            echo "</form>";
            echo '</tr>';

        }
        echo "</table>";
        mysqli_free_result($result);

        $_SESSION["email"] = "$email";
    $_SESSION["firstname"] = "$firstname";


    } else{
        echo "no user.";
    }
} else{
    echo "ERROR: Could not able to execute $sql. " . mysqli_error($conn);
}



}
// Close connection
mysqli_close($conn);
?>

<!DOCTYPE html>
<html>
  <head>
    <meta charset="utf-8">
    <title></title>
  </head>
  <body>
    <form class="" action="selectUser.php" method="post">
    username  <input type="text" name="username">
    <input type="submit" name="" value="test">
    </form>
  </body>
</html>

我的更新代码：

 <?php
   include('connection.php');
   session_start();

   $firstname = $_SESSION["firstname"];
   $email = $_SESSION["email"];

if ($email == "") {

  echo "lname  ej"; 
}
if ($firstname == ""){
    echo "fname gick ej"; 
}
else {

  $sql_update = mysqli_query($conn,"UPDATE employee SET firstname = '$firstname', WHERE email = '$email'");

}

  mysqli_close($conn);


?>

我是PHP的新手，但有Java和C＃的经验。思想过程是一样的吗？

谢谢！

如何从textarea获取信息到另一个PHP站点

0 个答案: