Question

我使用 Firebase云消息传递从服务器向移动设备发送消息，因此我创建了一个从FirebaseMessagingService扩展并覆盖onMessageReceived(RemoteMessage remoteMessage)的类我正在调用已实现的方法notifyUser(String from, String notification)。反过来，此方法调用属于类showNotification(String from, String notification, Intent intent)的另一个方法myNotificationManager，我在其中创建通知。问题是我需要启动一个片段而不是一个活动。有什么想法怎么做？提前谢谢。

public class ServicioFirebaseMessaging extends FirebaseMessagingService {

@Override
public void onMessageReceived(RemoteMessage remoteMessage){   
              notifyUser(remoteMessage.getFrom(),remoteMessage.getNotification().getBody());}

public void notifyUser(String from, String notification){

//Create an object of the class that contain the method which creates the notification

 MyNotificationManager myNotificationManager = new MyNotificationManager(getApplicationContext());

//Create an Intent that will be passed as a parameter in the method that creates the
//notification. This intent will be executed when user clicks on the notification. ShowMessage is a class in which 
//I define some TextView and other elements to show the message

Intent intent = new Intent(getApplicationContext(),ShowMessage.class); 

//put some values in the intent
//.......................

//calls the method that creates the notification
  myNotificationManager.showNotification(from,notification,intent);
  }
}

班级MyNotificationManager的代码：

public class MyNotificationManager {

//Activity context
private Context ctx;
//Notification id.
public static final int NOTIFICATION_ID = 234;
//Sound for notification
Uri uri= RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);

//Constructor
public MyNotificationManager(Context ctx) {
    this.ctx = ctx;
}

public void showNotification (String from, String notification, Intent intent){
//Define an Intent and actions to perform when called
    PendingIntent pendingIntent = PendingIntent.getActivity(
            ctx,
            NOTIFICATION_ID,
            intent,
            PendingIntent.FLAG_UPDATE_CURRENT);
    //To configre the notification
    NotificationCompat.Builder builder = new NotificationCompat.Builder(ctx);
    Notification mNotification = builder.setSmallIcon(R.mipmap.ic_launcher)
            //define notification parameters
            .setAutoCancel(true)
            .setContentIntent(pendingIntent)
            .setContentTitle(from)
            .setContentText(notification)
            .setSound(uri)
            .setSmallIcon(R.mipmap.ic_face)
            .setLargeIcon(BitmapFactory.decodeResource(ctx.getResources(),R.mipmap.ic_face))
            .build();

    //Define notification flags
    mNotification.flags |= Notification.FLAG_AUTO_CANCEL;

    //Notify user about received message
    NotificationManager notificationManager = (NotificationManager)ctx.getSystemService(Context.NOTIFICATION_SERVICE);

    //Execute notification
    notificationManager.notify(NOTIFICATION_ID,mNotification);
 }

}//end of class

Answer 1

我找到了办法。我调用MainActivity.class而不是让Intent调用ShowMessage.class。现在，MainActivity（一般应用程序）可以通过两种方式启动：

默认访问应用：用户点按应用的图标并访问应用（MainActivity）。
用户点击通知并通过在ServicioFirebaseMessaging类中扩展FirebaseMessagingService的notifyUser（String from，String notification）方法上实现的Intent访问应用程序（MainActivity）。在这个Intent中，我传递了一些将在MainActivity上使用的值。

现在的不同之处在于我已经在MainActivity中实现了额外的操作，被try / catch和'if'条件所包围，如果用户以第一种方式访问应用程序，则没有执行Intent然后没有从Intent获取的数据因为它甚至不存在（getIntent（）。getExtras.getSomething（）将失败），因为这个操作被try / cath所包围，app不会掉线。如果用户以第二种方式访问应用程序，那么try / catch中的操作将发生，因为'if'条件将为真，并且在这组操作中执行对相关片段的调用（FragmentSelectedMessage），传递给片段意图的值。当然，现在片段有一个支持它的活动。

如何从showNotification（）函数启动片段而不是活动（Intent）？

1 个答案: