面对T-sql Datediff功能的问题, 我计算两个日期之间的分钟日期差异,然后是几小时。
分钟给我正确的结果
SELECT DATEDIFF(minute,'2018-01-22 23:59:00.000','2018-01-23 00:44:00.000')
Result 45 minutes
但是,当我试图计算小时时,它会给我不正确的结果,几天结束,新的一天开始, 因此,如果时间参数为'23:59:00'且第二个参数为'00:44:00',则仅在45分钟时返回1小时差异。
SELECT DATEDIFF(HOUR,'2018-01-22 23:59:00.000','2018-01-23 00:44:00.000')
Result 1 Hour --Incorrect
我期待这个结果为零
SELECT DATEDIFF(HOUR,'2018-01-22 23:59:00.000','2018-01-23 00:44:00.000')
Result 0 Hour -- This is the result expected
更新 如果有人需要以格式日:小时:分钟
计算两个日期之间的差异,请在此处发布我的函数ALTER FUNCTION [dbo].[UDF_Fedex_CalculateDeliveryOverdue]
(
-- Add the parameters for the function here
@requiredDate VARCHAR(50),
@deliveryStamp VARCHAR(50)
)
RETURNS VARCHAR(25)
AS
BEGIN
DECLARE @ResultVar VARCHAR(25)
SET @ResultVar = ( SELECT CASE WHEN a.Days = 0 AND a.Hours = 0 THEN CAST(a.Minutes AS VARCHAR(10)) + ' Minutes'
WHEN a.Days = 0 THEN CAST(a.Hours AS VARCHAR(10)) + ' Hours ' + CAST(a.Minutes AS VARCHAR(10)) + ' Minutes'
ELSE CAST(a.Days AS VARCHAR(10)) +' Day ' + CAST(a.Hours AS VARCHAR(10)) +' Hours ' + CAST(a.Minutes AS VARCHAR(10)) + ' Minutes'
END
FROM ( SELECT DATEDIFF(hh, @requiredDate,@deliveryStamp)/24 AS 'Days'
,(DATEDIFF(MI, @requiredDate,@deliveryStamp)/60) -
(DATEDIFF(hh, @requiredDate,@deliveryStamp)/24)*24 AS 'Hours'
,DATEDIFF(mi, @requiredDate,@deliveryStamp) -
(DATEDIFF(mi, @requiredDate,@deliveryStamp)/60)*60 AS 'Minutes'
) a)
-- Return the result of the function
RETURN @ResultVar
END
答案 0 :(得分:2)
要获得值0,您需要在几分钟内得到结果,然后转换为小时:
SELECT DATEDIFF(minute,'2018-01-22 23:59:00.000','2018-01-23 00:44:00.000')/60
更精确:
SELECT DATEDIFF(minute,'2018-01-22 23:59:00.000','2018-01-23 00:44:00.000')/60.0