Question

面对T-sql Datediff功能的问题，我计算两个日期之间的分钟日期差异，然后是几小时。

分钟给我正确的结果

SELECT DATEDIFF(minute,'2018-01-22 23:59:00.000','2018-01-23 00:44:00.000')
Result 45 minutes

但是，当我试图计算小时时，它会给我不正确的结果，几天结束，新的一天开始，因此，如果时间参数为'23：59：00'且第二个参数为'00：44：00'，则仅在45分钟时返回1小时差异。

SELECT DATEDIFF(HOUR,'2018-01-22 23:59:00.000','2018-01-23 00:44:00.000')
Result 1 Hour --Incorrect

我期待这个结果为零

SELECT DATEDIFF(HOUR,'2018-01-22 23:59:00.000','2018-01-23 00:44:00.000')
Result 0 Hour -- This is the result expected

更新如果有人需要以格式日：小时：分钟

计算两个日期之间的差异，请在此处发布我的函数

ALTER FUNCTION [dbo].[UDF_Fedex_CalculateDeliveryOverdue] 
(
    -- Add the parameters for the function here
    @requiredDate VARCHAR(50), 
    @deliveryStamp VARCHAR(50)
)
RETURNS VARCHAR(25)
AS
BEGIN

DECLARE @ResultVar VARCHAR(25)

 SET @ResultVar = ( SELECT CASE WHEN a.Days = 0 AND a.Hours = 0 THEN CAST(a.Minutes AS VARCHAR(10)) + ' Minutes'
                                WHEN a.Days = 0  THEN CAST(a.Hours AS VARCHAR(10)) + ' Hours ' + CAST(a.Minutes AS VARCHAR(10)) + ' Minutes'
                                ELSE CAST(a.Days AS VARCHAR(10)) +' Day ' + CAST(a.Hours AS VARCHAR(10)) +' Hours ' + CAST(a.Minutes AS VARCHAR(10)) + ' Minutes'

                                    END 

FROM ( SELECT DATEDIFF(hh, @requiredDate,@deliveryStamp)/24 AS 'Days'
        ,(DATEDIFF(MI, @requiredDate,@deliveryStamp)/60) - 
        (DATEDIFF(hh, @requiredDate,@deliveryStamp)/24)*24 AS 'Hours'
        ,DATEDIFF(mi, @requiredDate,@deliveryStamp) - 
        (DATEDIFF(mi, @requiredDate,@deliveryStamp)/60)*60 AS 'Minutes'
        ) a)
    -- Return the result of the function

    RETURN @ResultVar
END

Answer 1

要获得值0，您需要在几分钟内得到结果，然后转换为小时：

SELECT DATEDIFF(minute,'2018-01-22 23:59:00.000','2018-01-23 00:44:00.000')/60

更精确：

SELECT DATEDIFF(minute,'2018-01-22 23:59:00.000','2018-01-23 00:44:00.000')/60.0

当差异仅为45分钟时，T-SQL DATEDIFF返回结果1小时

1 个答案: