Question

我是CI / PHP /开发的新手。我坚持这个问题。这似乎是非常基本但我不能正确！在sql执行时，我只能返回最后一个值。

控制器

$data['leadd']= $this->dashboard_model->countt($this->session->userdata('user_id'));

     foreach ($data['leadd'] as $q) { $date = $q['followup_date'];

     $data['lead']= $this->dashboard_model->lead_count($this->session->userdata('user_id'),$date); }

     $data['count'] = count($data['lead']);

模型

public function countt($userid)
{
    $sql = $this->db->query("SELECT followup_date FROM tg_partner_data WHERE assign_to = '$userid' AND active = 'Y'");

    return $sql->result_array();
}

public function lead_count($userid,$date)
{   
    $sql1 = $this->db->query("SELECT * FROM tg_partner_data
                             WHERE assign_to = '$userid' AND followup_date = '$date'
                             AND active='Y'");
    //echo $this->db->last_query();

    return $sql1->result_array();
}

Answer 1

首先，通过执行以下操作从一个表中选择所有后续日期：＆＃34; SELECT followup_date FROM tg_partner_data WHERE assign_to =＆＃39; $ userid＆＃39; AND active =＆＃39; Y＆＃39;＆＃34;。

然后对于每个followup_date，您执行另一个查询，但是您没有合并prevoius结果只是在foreach循环中覆盖它们。

Foreach循环应如下所示：

$data['lead'] = array();
foreach ($data['leadd'] as $q) { 
    $date = $q['followup_date'];
$data['lead'][] = $this->dashboard_model->lead_count($this->session->userdata('user_id'),$date));
}

您还可以重写SQL查询： SELECT COUNT（*）FROM tg_partner_data WHERE assign_to =＆＃39; $ userid＆＃39;和followup_date =＆＃39; $ date＆＃39; AND active =＆＃39; Y＆＃39;＆＃34;

它允许您直接从DB获取行数。

查询仅在codeigniter中查找最后一个值

1 个答案: