Question

我想回到JSON格式两个独立的数组。现在，我正在返回一个List并在那里填写所有数据。

如何创建一个具有两个数组的对象，并在一个数组中填充Station，Ime和Cell以及TA，RH，WS，SR，APRES和其他数组。

我有一个有3个对象的课程。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace WebAPI2.Models

{

public class Stations
{
    public string Station { get; set; }

    public string Ime { get; set; }

    public string Cell { get; set; }



  }

public class otherData
{
    public string DATS { get; set; }

    public string TA { get; set; }

    public string RH { get; set; }

    public string WS { get; set; }

    public string SR { get; set; }

    public string APRES { get; set; }
}

public class getAllValues
{
    public List<Stations> Stations { get; set; }

    public List<otherData> Data { get; set; }
    }
}

在ValuesController中，我创建了两个带有两个单独列表的foreach，但我不知道如何返回它们。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Net;
using System.Net.Http;
using System.Web.Http;
using MySql.Data.MySqlClient;
using System.Data;
using WebAPI2.Models;

namespace WebAPI2.Controllers
{

[RoutePrefix("API/Stations")]

public class ValuesController : ApiController
{

    [Route("")]
    // GET api/values

    public IEnumerable<getAllValues> Get()
    {
        MySqlConnection conn = WebApiConfig.conn();

        try
        {
            conn.Open();
        }
        catch (MySql.Data.MySqlClient.MySqlException ex)
        {
            string err = "Error: " + ex;
        }

        MySqlCommand executeStations = new MySqlCommand("select Stationsall.station,stationsall.Ime,Cell from stationsall join stations_cells using (Station);", conn);

        MySqlCommand executeData = new MySqlCommand("CALL Get_mod_cell_values_meteogram ('2018-01-27 00:00:00',42020,5);", conn);

        MySqlDataAdapter da = new MySqlDataAdapter(executeStations);

        MySqlDataAdapter da1 = new MySqlDataAdapter(executeData);

        DataTable dt = new DataTable();

        DataTable dt1 = new DataTable();

        da.Fill(dt);

        da1.Fill(dt1);

        List<Stations> Stations = new List<Stations>();

        foreach (DataRow dr in dt.Rows)
        {
            Stations getAllStations = new Stations
            {
                Station = dr["station"].ToString(),
                Ime = dr["Ime"].ToString(),
                Cell = dr["Cell"].ToString()
            };

            Stations.Add(getAllStations);              

            //returnedData(dr["station"].ToString(), dr["Ime"].ToString(), dr["Cell"].ToString());
        }

        List<otherData> otherData = new List<otherData>();

        foreach (DataRow dr1 in dt1.Rows)
        {
            otherData getAllData = new otherData
            {
                DATS = dr1["DATS"].ToString(),
                TA = dr1["TA"].ToString(),
                RH = dr1["RH"].ToString(),
                WS = dr1["WS"].ToString(),
                SR = dr1["SR"].ToString(),
                APRES = dr1["APRES"].ToString()
            };

            otherData.Add(getAllData);
        }

        return /*how to return otherData and Stations ?*/;


        }      
    }
}

Answer 1

您可以为所有数据制作separete视图模型。你需要3个clases： 1）

public class StationViewModel
{

    public string Station { get; set; }

    public string Ime { get; set; }

    public string Cell { get; set; }
}

第二

public class DataViewModel
{
    public string DATS { get; set; }

    public string TA { get; set; }

    public string RH { get; set; }

    public string WS { get; set; }

    public string SR { get; set; }

    public string APRES { get; set; }
}

第三

public class TableViewModel
{
     public List<StationViewModel> Stations { get; set; }

     public List<DataViewModel> Data { get; set; }
}

然后从Yours对象到新视图模型的映射。

修改

试试这个：

var getAllValuesList = new List<getAllValues>() { new getAllValues() { Stations = Stations, Data = otherData } }; return getAllValuesList;

如何构造Json格式以在Web API MVC中返回两个数组

1 个答案: