Question

下面有2个表

WITH id_tags AS
(
  SELECT 1 as ID, ['Michael','New York'] as tags UNION ALL
  SELECT 2 as ID, ['Michael','Jon', 'Texas'] as tags UNION ALL
  SELECT 3 as ID, ['abcd','Washington'] as tags UNION ALL
  SELECT 4 as ID, ['Washington','New York','Michael'] as tags UNION ALL
  SELECT 5 as ID, ['America','Michael'] as tags UNION ALL
  SELECT 6 as ID, ['Washington','Michael', 'defg'] as tags UNION ALL
  SELECT 7 as ID, ['America','Burqq','defg'] as tags
),
tagsCategory AS(
  SELECT 'Michael' as tags, 'Person' as category UNION ALL
  SELECT 'Burqq' as tags, 'Person' as category  UNION ALL
  SELECT 'New York' as tags, 'City' as category UNION ALL
  SELECT 'Washington' as tags, 'City' as category UNION ALL
  SELECT 'Texas' as tags, 'City' as category
)

我想显示一个例外列表。例外列表是id_tags有0或超过1人当id_tags有0或超过1个城市时。（基本上，每个类别只有1个）

预期结果：

----------------------------------
ID |  Reason                      
----------------------------------
2  |    Person more than 1        
3  |    Only 1 city  
4  |    More than 1 city detected    
5  |    No City Detected 
7  |    No City Detected

解释

ID 1 is totally fine, it has 1 City and has 1 person therefore it is not in the list
ID 2 it is because it has 2 people 
ID 3 because it has 1 city. we can ignore 'abcd' as it is not in the tags category
ID 4 is is because it has 2 cities
ID 5 because America is not city and therefore no city in that row
ID 6 is fine. We can ignore 'defg' as it is not in the list
ID 7 (the same reason as ID 5)

乍一看，我看起来很容易，但是，我总是在查询中发现错误。您对逻辑甚至查询示例有什么建议/帮助吗？

我使用standardBigQuery。

Answer 1

WITH id_tags AS
(
  SELECT 1 AS ID, ['Michael','New York'] AS tags UNION ALL
  SELECT 2 AS ID, ['Michael','Jon', 'Texas'] AS tags UNION ALL
  SELECT 3 AS ID, ['abcd','Washington'] AS tags UNION ALL
  SELECT 4 AS ID, ['Washington','New York','Michael'] AS tags UNION ALL
  SELECT 5 AS ID, ['America','Michael'] AS tags UNION ALL
  SELECT 6 AS ID, ['Washington','Michael', 'defg'] AS tags UNION ALL
  SELECT 7 AS ID, ['America','Burqq','defg'] AS tags
),
tagsCategory AS(
  SELECT 'Michael' AS tags, 'Person' AS category UNION ALL
  SELECT 'Jon' AS tags, 'Person' AS category UNION ALL
  SELECT 'Burqq' AS tags, 'Person' AS category  UNION ALL
  SELECT 'New York' AS tags, 'City' AS category UNION ALL
  SELECT 'Washington' AS tags, 'City' AS category UNION ALL
  SELECT 'Texas' AS tags, 'City' AS category
)
SELECT id, 
  COUNTIF(category = 'City') AS cities, 
  COUNTIF(category = 'Person') AS names 
FROM id_tags, UNNEST(tags) tag
JOIN tagsCategory ON tag = tagsCategory.tags
GROUP BY id
HAVING NOT cities = 1 OR NOT names = 1

要与数组

1 个答案: