是否有可用于使用GL_TRIANGLES基元类型生成平面的算法?
这是我目前的职能:
Mesh* Mesh::CreateMeshPlane(vec2 bottomleft, ivec2 numvertices, vec2 worldsize){
int numVerts = numvertices.x * numvertices.y;
float xStep = worldsize.x / (numvertices.x - 1);
float yStep = worldsize.y / (numvertices.y - 1);
VertexFormat* verts = new VertexFormat[numVerts];
for (int y = 0; y < numvertices.y; y++)
{
for (int x = 0; x < numvertices.x; x++)
{
verts[x + (y * numvertices.x)].pos.x = bottomleft.x + (xStep * x);
verts[x + (y * numvertices.x)].pos.y = bottomleft.y + (yStep * y);
verts[x + (y * numvertices.x)].pos.z = 0;
}
}
Mesh* pMesh = new Mesh();
pMesh->Init(verts, numVerts, indices, 6, GL_STATIC_DRAW);
glPointSize(10.0f);
pMesh->m_PrimitiveType = GL_POINTS;
delete[] verts;
return pMesh;}
我只是不确定如何在for循环中实现索引,以便能够知道要绘制哪些点。
我认为我需要知道:
每个正方形将由2个三角形组成,每个正方形需要6个指数
目前我从左下角绘图
我需要知道我传给的数字中有多少个方格
答案 0 :(得分:0)
也许是这样的:
int width = 4;
int length = 6;
int height = 1;
std::vector<float> planeVertices;
for (int x = 0; x < width - 1; x++) {
for (int z = 0; z < length - 1; z++) {
planeVertices.push_back(x);
planeVertices.push_back(height);
planeVertices.push_back(z);
planeVertices.push_back(x);
planeVertices.push_back(height);
planeVertices.push_back(z + 1);
planeVertices.push_back(x + 1);
planeVertices.push_back(height);
planeVertices.push_back(z + 1);
planeVertices.push_back(x);
planeVertices.push_back(height);
planeVertices.push_back(z);
planeVertices.push_back(x + 1);
planeVertices.push_back(height);
planeVertices.push_back(z);
planeVertices.push_back(x + 1);
planeVertices.push_back(height);
planeVertices.push_back(z + 1);
}
}
...
unsigned int VBO, VAO;
glGenVertexArrays(1, &VAO);
glGenBuffers(1, &VBO);
glBindVertexArray(VAO);
glBindBuffer(GL_ARRAY_BUFFER, VBO);
glBufferData(GL_ARRAY_BUFFER, planeVertices.size() * sizeof(float), planeVertices.data(), GL_STATIC_DRAW);
glVertexAttribPointer(0, 3, GL_FLOAT, GL_FALSE, 3 * sizeof(float), 0);
glEnableVertexAttribArray(0);
...
glDrawArrays(GL_TRIANGLES, 0, (width - 1) * (length - 1) * 6);
此代码创建std::vector<float>
并将平面顶点添加到其中。嵌套的for
循环为平面的每个单元添加两个三角形(因此,width
为4,length
为6,平面将为4个单位乘以6个单位,并且将由6 * 4 * 2 = 48个三角形)。平面的高度由height
变量设置。这只会生成平面,但通过简单的变换,您可以根据需要旋转和缩放。
警告:此代码未经测试。
答案 1 :(得分:0)
在这里关闭这个问题我是怎么做到的:
Mesh* Mesh::CreateMeshPlane(vec3 bottomleft, ivec2 numvertices, vec2
worldsize, vec2 texturerepetition)
{
int numVerts = numvertices.x * numvertices.y;
int numFaces = (numvertices.x - 1) * (numvertices.y - 1);
int numIndices = numFaces * 6;
float xStep = worldsize.x / (numvertices.x - 1);
float yStep = worldsize.y / (numvertices.y - 1);
float zStep = worldsize.y / (numvertices.y - 1);
float uStep = texturerepetition.x / (numvertices.x - 1);
float vStep = texturerepetition.y / (numvertices.y - 1);
VertexFormat* verts = new VertexFormat[numVerts];
unsigned int* indices = new unsigned int[numIndices];
for (int y = 0; y < numvertices.y; y++)
{
for (int x = 0; x < numvertices.x; x++)
{
verts[x + (y * numvertices.x)].pos.x = bottomleft.x + (xStep * x);
verts[x + (y * numvertices.x)].pos.y = bottomleft.y;
verts[x + (y * numvertices.x)].pos.z = bottomleft.z + (zStep * y);
verts[y * numvertices.x + x].uv.x = uStep * x;
verts[y * numvertices.x + x].uv.y = vStep * y;
}
}
int offset = 0;
for (int i = 0; i < numIndices; i++)
{
// The bottom left index of the current face
// + the offset to snap back when we hit the edge
unsigned int cornerIndex = i/6 + offset;
// If we reach the edge we increase the offset so that it goes to the next bottom left
if ((cornerIndex + 1)%numvertices.x == 0)
{
offset++;
cornerIndex++; // Adding new offset to the bottom left
}
// First triangle
indices[i] = (unsigned int)cornerIndex;
i++;
indices[i] = (unsigned int)cornerIndex + numvertices.x;
i++;
indices[i] = (unsigned int)cornerIndex + numvertices.x + 1;
i++;
// Second triangle
indices[i] = (unsigned int)cornerIndex;
i++;
indices[i] = (unsigned int)cornerIndex + numvertices.x + 1;
i++;
indices[i] = (unsigned int)cornerIndex + 1;
}
//glPolygonMode(GL_FRONT_AND_BACK, GL_LINE);
Mesh* pMesh = new Mesh();
pMesh->Init(verts, numVerts, indices, numIndices, GL_STATIC_DRAW);
delete[] verts;
return pMesh;
}
工作流: 1.计算我需要的面数,然后计算指数 2.当我们意识到我们到达顶点数组的边缘时(通过使用模数numvertices.y),创建一个添加到cornerIndex的偏移量 3.根据cornerIndex
进行简单的数学计算,以正确的顺序绘制角点注意: 1.我使用GL_TRIANGLES作为基本类型绘图 2.从左下角到右上角绘图 3. cornerIndex因此是我们在
上绘制的当前正方形的左下角希望有人能发现这有用!