Question

这是我的刽子手游戏代码。我无法弄清楚如何检查他们输入的字母是否在单词中，然后检查字母序列是否等于单词中的字母。

感谢您的帮助。

import sys
import random
answers = [ a long list of possible answers all correctly formatted :d ]

again =""
num = 0

win = True

while again == "":
    contin = input("""
            ...Hangman...
            enter to play
            ['stop'] to stop
""")

    again = contin.title()
    if again == "":
        num = random.randint(0,len(answers)-1)
        word = answers[num]
        tries = len(word)+10
        print(word)



        while   :
            guessmessage ="guess a letter.... You have ",tries,"tries: "
            guess = input(guessmessage)


            if tries != len(word)+10:

                for letter in word:

                    if guess != letter:
                        print(" ")
                        tries = tries - 1

                    else:
                        print(letter)
                        tries = tries - 1

        else:

            sys.exit("You Have Ran Out Of Attempts..... Better Luck Next Time!")

else:
    sys.exit("You Have Quit The Game! :(  ")

Answer 1

我不明白你的意思“检查字母序列是否等于单词”中的字母。请举例说明您希望在该部分实现的目标。

至于检查'字母'中的'字母'是否在猜测中，您可以使用以下代码执行此操作：

answer = "hangman"
guess = 'a'

if guess in word:
    print("Letter", guess, "is in the answer.")
else:
    print("Letter", guess, "is not in the answer.)

我只是使用if-else作为示例，但基本上语法与letter in word一样简单。

Hangman游戏用什么来保持代码运行

1 个答案: