我有一个很长的CloudKit函数，它位于for循环中，基本上以返回元组结束。
func loadTuple(members: [String], anotherTeam: Bool) -> [(String, Double)]{
var temp = [(String, Double)]()
var tempTuple = [(String, Double)]()
// make sure it is empty again
grouplyHours = [Double]()
if (members.count > 0){
for x in 0 ..< members.count{
// loops through each group member
let pred2 = NSPredicate(format: "username = %@", members[x])
let query2 = CKQuery(recordType: "PersonalUser", predicate: pred2)
let operation2 = CKQueryOperation(query: query2)
//operation.resultsLimit = CKQueryOperationMaximumResults
operation2.recordFetchedBlock = { (record2: CKRecord!) in
operation2.qualityOfService = .userInteractive
if record2 != nil{
self.userGroupRecordToUpdate = record2
// takes the groupNames list of the user just accepted
acceptedUsersArray = (record2.object(forKey: "userGroups") as! Array)
self.addedUser = members[x]
grouplyHours = (record2.object(forKey: "hoursExercisedGrouply") as! Array)
//self.feedTableView.reloadData()
// tprintw(groupNames.count)
// not adjusting grouply thingy in time or at all idk, try a different apparoach
}
operation2.queryCompletionBlock = { [unowned self] (cursor, error) in
DispatchQueue.main.async {
if error == nil {
innerLoop: for i in 0 ..< acceptedUsersArray.count{
//tprintw("grouplyHours: \(grouplyHours)")
// for each person, loops through to find their index that is this group name
if acceptedUsersArray[i] == self.groupNameLbl.text{
// if you find the index that has the group name, now take the same index of the hours and add it to the tuple
// still accessing the first person's grouplyhours array
if (members.count - 1 >= x && grouplyHours.count - 1 >= i){
tempTuple.append((members[x], grouplyHours[i]))
}
break innerLoop
}
}
// for loop ends
if (anotherTeam == true){
temp = tempTuple.sorted(by: {$0.1<$1.1})
temp = temp.reversed()
}else{
sortedTupleArray = tempTuple.sorted(by: {$0.1<$1.1})
sortedTupleArray = sortedTupleArray.reversed()
if sortedTupleArray.count > 0{ // should be more than 0 since there is always someone in the group
self.leadingUserInTeamLbl.text = sortedTupleArray[0].0
}
}
}
}
}
}
// 7 total
database.add(operation2)
// end of loops
}
}
addedUser = username
self.onlyLoadGrouplyHoursForThisGroup()
if anotherTeam == true{
return temp
}
print("sta: \(sortedTupleArray)")
return sortedTupleArray
// put group hours array back to the current user using the app
}
当我说：
时，我在代码中更早地调用了上面的函数tupleRankings = self.loadTuple(members: groupMembs, anotherTeam: false)
print(tupleRankings) // shows up as empty
我在上面的这一行后面有一条打印行，除了它说元组是空的。同时，我在long函数的最后一行有一个打印行，它打印出一个带有值的元组（函数中的正确响应）。
我需要一种方法来检查在执行打印行之前是否完成了该功能。有没有一种简单的方法可以让你们想出来？