我有一个PHP代码,如果用户raffle1
及其1
,则会将用户的steamid = '$a'
列更改为name like '% royalcodes.com'
。
我只是想知道如果它具有我之前展示的内容,我将如何显示消息。
我试过这样的。这是完整的代码..
if(!isset($_SESSION['steamid'])) {
//Nah
} else {
include ('steamauth/userInfo.php');
$a=$steamprofile['steamid'];
$b=$steamprofile['personaname'];
}
if (isset($_POST['raffle1'])) {
$query = "UPDATE users SET raffle1 = '1' WHERE name LIKE '% royalcodes.com' AND steamid = '$a'";
$result = mysqli_query($conn, $query);
$query2 = "SELECT * FROM NOT LIKE '% royalcodes.com'";
$result22 = mysqli_query($conn, $query2);
if ($result) {
$smsg = "Succesfully registered to the raffle. Good luck!";
} else if($result22) {
$fmsg = "Put royalcodes.com to enter the raffle!";
}
}
if (isset($_SESSION['raffle1'])){
$username = $_SESSION['raffle1'];
header("Location: raffle1.php");
} else {
#Here I have some html code then I have this in a div
if (isset($smsg)) { ?>
<div role="alert"> <?php echo $smsg; ?> </div><?php
}
if (isset($fmsg)) {
?><div role="alert"> <?php echo $fmsg; ?> </div><?php
}
#Closing the file with php syntax
}