Question

Golang删除特定字符串的方法有很多种。但是我现在需要使用正则表达式。

func Replace(path, from, to string) string {
    reg, _ := re.Compile(from)
    if reg.MatchString(path) {
        return reg.ReplaceAllString(path, to)
    }
    return "error"
}

//This pattern is OK
fmt.Println(Replace("/nl/amsterdam/area2/area1", `\/+(?:area1|area2).+(/|\z)`, "$1"))
// Output: /nl/amsterdam

//What is wrong??
fmt.Println(Replace("/nl/amsterdam/area2", `\/+(?:area1|area2).+(/|\z)`, "$1"))
// Output: error
// I expect => /nl/amsterdam

fmt.Println(Replace("/nl/amsterdam/area2", `\/+(?:area1|area2)(/|\z)`, "$1"))
// Output: /nl/amsterdam
// This pattern seems OK, but when path is `/nl/amsterdam/area2/area1`, it doesn't work as I expected like the next pattern.

fmt.Println(Replace("/nl/amsterdam/area2/area1", `\/+(?:area1|area2)(/|\z)`, "$1"))
// Output: /nl/amsterdam/area1
// I wanna get /nl/amsterdam

路径中包含的目标数量可以更改。

Answer 1

您可以使用以下正则表达式：

(?:/(?:area1|area2))+(/|$)

请参阅regex demo。

<强>详情

(?:/(?:area1|area2))+ - 出现以下一个或多个序列：
- / - 一个/字符（无需在Go正则表达式模式中将其转义）
- (?:area1|area2) - 与area1或area2匹配的非捕获组（也可以替换为area[12]或仅area\d+来匹配{{1}和1+位数）
area - 第1组：(/|$)或字符串结尾（/将匹配字符串的结尾）。

通过regexp从url路径中删除特定路径

1 个答案: