Question

如何从CakePHP 3中的查询对象中获取'params'？

$response = $this->getTable()->find();
// there are beforeFinds...etc that make this more complex

当我调试$response时，我得到了这个（：

// ...
'(help)' => 'This is a Query object, to get the results execute or iterate it.',
'sql' => 'SELECT .... WHERE ... article_id = :c2',
'params' => [
    ':c0' => [
        [maximum depth reached]
    ],
    ':c1' => [
        [maximum depth reached]
    ],
    ':c2' => [
        [maximum depth reached]
    ]
],
// ...

我想知道:c2的价值是什么，但我似乎无法调试params。

我试过这些：

\Cake\Error\Debugger::log($response->params);
\Cake\Error\Debugger::log($response->params());
\Cake\Error\Debugger::log($response['params']);
\Cake\Error\Debugger::log($response->getParams());
\Cake\Error\Debugger::log($response->getQueryParams());

但没有工作。

Answer 1

通过增加调试的深度，我能够看到有条件的信息，包括:c2的值

\Cake\Error\Debugger::log($response, 'debug', 4); // default depth is 3

Answer 2

您应该可以通过$response->valueBinder()->bindings()获取它们。

Answer 3

您可以使用__debugInfo()方法：

$result = $this->Pages->find()->where(['is_public' => 1]);

dd($result->__debugInfo()['params']);

如何从CakePHP 3中的查询对象获取params

3 个答案: