尝试运行以下PHP文件时出现以下错误:
SQLite3Stmt :: execute()需要0个参数,给定1个(第34行)
和
调用未定义的方法SQLite3Stmt :: fetch()(第36行)
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>
<?php
class MyDB extends SQLite3
{
function __construct()
{
$this->open('Users.db');
}
}
$db = new MyDB();
$email_address = $_POST['email_address'];
$password = $_POST['password'];
$email_address =($email_address);
$password =($password);
$email_address = intval($_POST["email_address"]);
$password = intval($_POST["password"]);
$sql = "SELECT * FROM user_info WHERE email_address='$email_address' AND
password='$password WHERE email_address=? AND where password=?'";
$stmt = $db->prepare($sql);
$stmt->bindParam(1, $email_address);
$stmt->bindParam(2, $password);
$result = $stmt->execute($sql);
while($column = $stmt->fetch())
{
echo $column["email_address"];
echo $column["password"];
};
if($email_address==1){
echo "<h1>Logged In</h1>";
};
?>
<body>
</body>
</html>
这是一个简单的登录页面,它连接到SQLite数据库,然后登录时返回。
答案 0 :(得分:0)
错误信息非常简单。在不需要执行方法的情况下,您将为执行方法提供参数。
$stmt->execute();