我正在尝试从starttime
中提取一周中的月,小时和星期几。
City: NYC
OrderedDict([('tripduration', '839'),
('starttime', '1/1/2016 00:09:55'),
('stoptime', '1/1/2016 00:23:54'),
('start station id', '532'),
('start station name', 'S 5 Pl & S 4 St'),
('start station latitude', '40.710451'),
('start station longitude', '-73.960876'),
('end station id', '401'),
('end station name', 'Allen St & Rivington St'),
('end station latitude', '40.72019576'),
('end station longitude', '-73.98997825'),
('bikeid', '17109'),
('usertype', 'Customer'),
('birth year', ''),
('gender', '0')])
datum_n_m = example_trips['NYC'][datetime.strptime('starttime','%m/%d/%Y %H:%M:%S')]
ValueError:时间数据' starttime'不符合格式'%m /%d /%Y%H:%M:%S'
答案 0 :(得分:1)
首先,让我们制作一个[mcve]
# you do need to import stuff
from datetime import datetime
# the ordered dict is irrelevant, so get rid of it
# this reproduces the error
print (datetime.strptime('starttime','%m/%d/%Y %H:%M:%S'))
重现
builtins.ValueError:时间数据'starttime'与格式'%m /%d /%Y%H不匹配:%M:%S'
这是因为字符串“starttime”不是该格式的时间。这只是几封信。如果你已经做了一个基本的[mcve],你就可以解决自己的问题。基本调试:)
也许你的意思是:
start_time_as_string = example_trips['NYC']['starttime']
datum_n_m = datetime.strptime( start_time_as_string )