Question

此代码从s3获取所有对象并删除对象从getAllObjects调用DeletePhotosFromS3。

我在objects中的DeletePhotosFromS3中获得2个不同的密钥但是deleteObjects有两个相同的密钥。前[{Key: 1}, {Key: 1}]。

为什么deleteObjects有两个相同的密钥以及如何在objects中设置[]*s3.ObjectIdentifier？

func getAllObject(userID string) (*[]string, error) {
    var objects []string

    svc := initS3()
    config := model.NewConfig()

    input := &s3.ListObjectsInput{
        Bucket:  aws.String(config.AWSS3Bucket),
        Prefix:  aws.String(userID),
        MaxKeys: aws.Int64(2), // default 1000
    }

    result, err := svc.ListObjects(input)
    if err != nil {
        return &objects, err
    }

    for _, v := range result.Contents {
        objects = append(objects, *v.Key)
    }

    return &objects, nil
}

func DeletePhotosFromS3(userID string) (error) {
    var deleteObjects []*s3.ObjectIdentifier

    svc := initS3()
    config := model.NewConfig()

    objects, err := getAllObject(userID) // called getAllObject
    for _, v := range *objects {
        deleteObjects = append(deleteObjects, &s3.ObjectIdentifier{Key: &v}) // Er
    }
    ... 
}

Answer 1

for循环中的迭代值v将在每次迭代时重用。指针&v对于附加到列表的每个项目都是相同的。修正了片段：

for _, v := range *objects {
        vcopy := v
        deleteObjects = append(deleteObjects, &s3.ObjectIdentifier{Key: &vcopy})
}

Go不能将字符串设置为struct

1 个答案: