Question

如何使用xpath获取元素的位置。例子。我有一个xml如下。

class Song(object):

  def _init_(self, lyrics):
    self.lyrics=lyrics
  def sing_me_a_song(self):
    for line in self.lyrics:
      print line

happy_bday = Song(["Happy birthday to you",
               "I dont want to get sued",
               "So I'll stop right there"])

bulls_on_parade = Song(["The rally around the family",
                    "with pockets ful of shales"])

happy_bday.sing_me_a_song()
bulls_on_parade.sing_me_a_song()

我正在尝试使用xpath表达式<a> <b> <c> <ID>12324234</ID> <FirstName>Something</FirstName> <LastName>Somethingelse</LastName> </c> <c> <ID>12324235</ID> <FirstName>Something</FirstName> <LastName>Somethingelse</LastName> </c> </b> </a>提取元素id。我坚持的是，我也想提取这个位置。

示例

/a/b/c/ID/text()

逗号只是为了理解。我可以使用上面提到的xpath将数据提取为第一步，然后使用xpath作为位置。请注意，数组可以有n个值，但不限于2。

我试过计数，位置等，但没有运气。任何人都可以建议我一些选择

Answer 1

You can try below XPath to get required output:

/a/b/c/concat(./ID/text(), ", ", (count(./preceding-sibling::c/ID) + 1))

Output:

12324234, 1
12324235, 2

使用xpath的数组位置

1 个答案: