Question

以下是我的User.rb

class User
  has_one :profile
  has_one :qualification
end

class Profile < ApplicationRecord
  belongs_to :user
end

class Qualification < ApplicationRecord
  belongs_to :user
end

现在，我想获取其profile.name如params或qualified.name的用户，如params。

我正在尝试以下代码，但收到错误：

User.joins(:profile, :qualification)
    .where("profiles.name like ?  
            or qualifications.name like ?", 
            "%#{params[:name]}%", 
            "%#{params[:name]}%")

我正在使用Ruby 2.4, Rails 5.1

以下是错误：

SELECT  `users`.* FROM `users` INNER JOIN `profiles` ON `profiles`.`user_id` = `users`.`id` INNER JOIN `qualifications` ON `qualifications`.`id` = `users`.`qualification_id` WHERE (profiles.name like %user9%) LIMIT 11
ActiveRecord::StatementInvalid: Mysql2::Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '%user9%) LIMIT 11' at line 1: SELECT  `users`.* FROM `users` INNER JOIN `profiles` ON `profiles`.`user_id` = `users`.`id` INNER JOIN `qualifications` ON `qualifications`.`id` = `users`.`qualification_id` WHERE (profiles.name like %user9%) LIMIT 11

配置文件和限定表包含user_id作为外键。我可以通过User.joins(:profile, :qualification)创建一个

来获取记录

喜欢在rails中嵌套关联中的查询

0 个答案: