Question

我尝试将list作为元素输入，但预期结果不是包含元素列表的列表。以下代码是否需要修改或是否不正确？

例如，[1,2,3] [3,4,5]，但结果与[[1,2,3] ,[3,4,5]]不一样

s = raw_input()
numbers = map(list , s.split())
print number

Answer 1

Your objective is to store the input lists into a list (say 'l'). Iterate over input string, store the string letters between '[' and ']' into a temp list (say list1) which can be tracked using simple if-condition, and append the collected lists (list1 into the main list ('l'):

l = list()

s = input("input plz")

for a in s:
    if a =='[':
        list1 = list()
    elif a ==']':
        l.append(list1)
    elif a !=',' and a!=' ':
        list1.append(int(a))

print(l)

Answer 2

s.split itself return list Try this

s = raw_input()
numbers = s.split()
print numbers

output

['2', '5', '6']

For multidimensional list

li=list()
s = raw_input()
while s!="Stop":
    li.append(s.split())
    s = raw_input()

print li

Output

[['2', '3', '5', '4'], ['2', '5', '63', '6'], ['2', '3', '56', '2']]

Answer 3

这可能是一种可能的解决方案。

s1 = []
ask = raw_input("Yes/No: ")
while ask == "Yes":
    s2 = raw_input()
    lst_one = s2.split()
    s1.append(s2)
    print s1
    ask = raw_input("Yes/No: ")

如何制作一个包含从用户输入中读取的元素列表的列表？

3 个答案: