Question

我有一个任务是编写一个程序来替换单词＆＃34; corgi＆＃34;等Noun，Place，PluralNoun等单词。我得到的代码90％正确，但我错过了标点符号，但我不知道为什么。这是我写的代码：

parts_of_speech  = ["PLACE", "PERSON", "PLURALNOUN", "NOUN"]

test_string = """This is PLACE, no NOUN named PERSON, We have so many PLURALNOUN around here."""

def word_in_pos(word, parts_of_speech):
    for pos in parts_of_speech:
        if pos in word:
            return word
    return None

def play_game(ml_string, parts_of_speech):   
    replaced =[]
    word=ml_string.split(" ")
    for w in word:
        print w
        con = word_in_pos(w,parts_of_speech)
        if con != None:
            replaced.append(w.replace(con,"corgi"))
        else:
            replaced.append(w)
    return " ".join(replaced)

print play_game(test_string, parts_of_speech)

Answer 1

word_in_pos()完整地返回参数word，包括其中的任何标点符号。因此，当您执行replace()时，您也会替换标点符号。相反，只需从pos返回word_in_pos()：

def word_in_pos(word, parts_of_speech):
    for pos in parts_of_speech:
        if pos in word:
            return pos
    return None

结果：

这是corgi，没有corgi名为corgi，我们周围有很多小狗。

在保持标点符号的同时替换字符串

1 个答案: