我有以下PHP代码,它通过键名搜索数组并将结果等于返回搜索。只是为了好奇我怎么能这样做,无论我搜索结果是什么,名称键值等于“A”的元素?我怎样才能检索名称为“A”的元素?
我尝试了以下但不起作用:
$jSearchResult[] = $ajProducts[$i]->name = "A";
请帮助我,因为我只是无法弄清楚如何通过键值来检索数组的元素,但是我确信它必须非常简单。
<?php
//DATA coming from the BROWSER
$sSearch = $_GET['search'];
//TURN it into UPPERCASE
strtoupper( $sSearch );
//GETTING from the TEXT FILE:
$sajProducts = file_get_contents( 'products.txt' );
$ajProducts = json_decode( $sajProducts );
$match_found = false;
//Collect all matching result in an array
$jSearchResult = array();
//LOOPING THROUGH THE ARRAY OF PRODUCTS
for ( $i=0; $i< count( $ajProducts ); $i++ ) {
if ( $sSearch == $ajProducts[$i]->name ) {
$jSearchResult[] = $ajProducts[$i]->name;
$match_found = true;
}
}
//if there is a match display the product
if ( $match_found ) {
echo json_encode ( $jSearchResult );
exit;
}
//if not display ALL products
else {
echo json_encode ( $ajProducts );
exit;
}
?>
$ajProducts
看起来像这样:
[
{
"id": "59d278cae7017",
"name": "A",
"price": "1",
"quantity": 2,
"image": "img_webshop\/productimage-59d74304917c2.jpg"
},
{
"id": "59d27e20c8028",
"name": "A",
"price": "2",
"quantity": 1,
"image": "img_webshop\/productimage-59d743233c0cf.jpg"
},
{
"id": "59d6a7ae16d15",
"name": "A",
"price": "3",
"quantity": 2,
"image": "img_webshop\/productimage-59d743392fbb5.jpg"
},
{
"id": "59d6d6ee5f752",
"name": "A",
"price": "4",
"quantity": 1,
"image": "img_webshop\/productimage-59d74352d5b94.jpg"
},
{
"id": "59d743d207bd5",
"name": "B",
"price": "5",
"quantity": 1,
"image": "img_webshop\/productimage-59d743d1e6e64.jpg"
},
{
"id": "59d74451225ac",
"name": "B",
"price": "6",
"quantity": 0,
"image": "img_webshop\/productimage-59d7445120871.jpg"
},
{
"id": "59e0d992d1f3b",
"name": "C",
"price": "6",
"quantity": 2,
"image": "img_webshop\/productimage-59e725ac79583.jpg"
}
]
答案 0 :(得分:3)
有一个PHP函数可以做到这一点:http://php.net/array_filter
$searchResult = array_filter($ajProducts, function ($product) {
return $product->name === 'A';
});
这将为$ajProducts
name
属性设置为'A'
的所有对象提供支持。
要查看是否有任何结果:
$matchFound = !empty($searchResult);
答案 1 :(得分:1)
如果您想要match
值name key
等于"A"
的{{1}}个元素,那么您可以使{name}的值check
等于{{1}喜欢 -
"A"