Question

我想从网址中提取html标签，但有些网站会返回未知字符... 我认为带有ajax编程的url有这个问题...... 这是我的代码

 SELECT pt.EmployeeID , pt.FirstName, pt.LastName, pt.[Address]
  FROM 
    (
        SELECT *
        FROM FlatFile.UserList

    ) AS temp
        PIVOT
        (
            MAX([COLUMN2])
            FOR [COLUMN1] IN ([EmployeeID],[FirstName],[LastName],[Address])
        ) as pt

它给我一个像这样的字符串

$url='http://www.varzesh3.com';
$ch=curl_init();
$timeout=5;

curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);

// Get URL content
$lines_string=curl_exec($ch);
// close handle to release resources
curl_close($ch);
//output, you can also save it locally on the server
echo $lines_string;

我该如何解决？... 我想要HTML标签内的内容

Answer 1

您在示例中提供的网站链接包含需要utf-8的阿拉伯语单词。它还返回gzip压缩数据。

您可以使用标题来支持页面上的utf-8

header('Content-type: text/html; charset=UTF-8');

并在您的卷曲请求中将CURLOPT_ENCODING设置为gzip

最终守则应

<?php
header('Content-type: text/html; charset=utf-8');

$url='http://www.varzesh3.com';
$ch=curl_init();
$timeout=5;

curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);

// We will set curl header to support utf-8 charset
curl_setopt($ch, CURLOPT_HTTPHEADER, array("Content-Type: text/html; charset=UTF-8"));
// We will support gzip encoded data
curl_setopt($ch, CURLOPT_ENCODING , "gzip");

// Get URL content
$lines_string=curl_exec($ch);
// close handle to release resources
curl_close($ch);
//output, you can also save it locally on the server
echo $lines_string;

Answer 2

如果是像json和xml这样的指定格式，Curl将获取数据。但你只是写url而不是特定的url，它以json或array或xml等方式发送数据。

如果您想下载整个网站，请使用命令行尝试CURL。

无法用php获取一些网址

2 个答案: