Question

要求是根据state-PASS对行进行编号，并按特定id的时间顺序排序：因此，当每次PASS发生在一个id的状态时，它应该对数字进行加密。如果没有发生传递，它应该保持数字

我目前正在尝试使用

rank() over (partition by id, user, state = 'PASS' order by time)

但这很有效，直到交替出现传球，但如果没有传球则不起作用

任何帮助将不胜感激。谢谢

这是样本数据：

ID  user    State    time          Req. number
-----------------------------------------------
1    a1     work     timestamp1     1
1    f1     pass     timestamp2     1
1    s1     work     timestamp3     2
1    f1     pass     timestamp4     2
1    m1     break    timestamp5     3
1    s1     pass     timestamp6     3
1    f1     work     timestamp7     4
1    a1     pass     timestamp8     4
1    v1     work     timestamp9     5
1    s1     endwork  timestamp10    5
1    s1     endwork  timestamp11    5
1    a1     work     timestamp12    5
2    a2     work     timestamp13    1
2    s2     endwork  timestamp14    1

Answer 1

您似乎想要比“前一行”的累计“通过”数量多一个：

select t.*,
       coalesce(sum(case when state = 'PASS' then 1 else 0 end) over
                    (partition by id
                     order by time
                     rows between unbounded preceding and 1 preceding
                    ) + 1, 1
               )
from t;

使用SQL在一列中发生特定值后更改行号

1 个答案: