Question

我不知道如何使用改造解析json 。熟悉使用Retrofit解析简单的json但不熟悉使用 Retrofit 解析嵌套的Json 。

这是我的Json数据.................

  {
         "current_observation": {
             "image": {
                 "url":"http://icons.wxug.com/graphics/wu2/logo_130x80.png",                
                 "title":"Weather Underground",
                 "link":"http://www.wunderground.com"
},
                  {
                  "url":"http://icons.wxug.com/graphics/wu2/logo_130x80.png",               
                 "title":"Weather Underground",
                 "link":"http://www.wunderground.com"
                   }
             }
         }
     }

任何帮助将不胜感激。谢谢。

这是我的简单json方法

public class Country {
    @SerializedName("current_observation")
    @Expose
    private List<Items> items;

    public List<Items> getItems() {
        return items;
    }

    public void setItems (List<Items> items) {
       this.items = items;
    }
}

来了......

 public class Items {
        @SerializedName("image")
        @Expose
        private String url;
        private String title;
        private String link;

        public String getFlag() {
            return url;
        }
        public String getRank() {
           return link;
        }
        public void setRank(String link) {
            this.link = link;
        }
        public void setFlag(String url) {
            this.url = url;
        }
        public String getCountryname() {
            return title;
        }
        public void setCountryname(String rating) {
            this.title = rating;
        }
    }

主要活动中的代码

Call <Country>  call = apiInterface.getCountries();

        call.enqueue(new Callback <Country>() {
            @Override
            public void onResponse(Call<Country> call, Response<Country>  response) {
                Log.d(TAG,"onSuccess Server Response "+ response.toString());

                Log.d(TAG,"onSuccess received information "+ response.body().toString());
                List<Items> items = response.body().getItems();
                adapter = new RecAdapter(items, getContext().getApplicationContext());
                recyclerView.setAdapter(adapter);

            }

Answer 1

使用Response

中的Retrofit课程下方

class Response{
   @SerializedName("current_observation")
   Observation observation;
   //getters and setters
}

class Observation{
   @SerializedName("image")
   Image image;
   //getters and setters
}

class Image{
  @SerializedName("title")
  String title;
  @SerializedName("link")
  String link;
  @SerializedName("url")
  String url;
  //getters and setters
}

Answer 2

如果正确实现Pojo，这将更容易。

你的班级和你的json有冲突。

来自您的国家/地区类，＆＃34; current_observation＆＃34;将是List<Items> items;

然后你的json应该是这样的：

"current_observation":[
{
     "image": {
         "url":"http://icons.wxug.com/graphics/wu2/logo_130x80.png",
         "title":"Weather Underground",
         "link":"http://www.wunderground.com"
     }
},
{
     "image": {
         "url":"http://icons.wxug.com/graphics/wu2/logo_130x80.png",
         "title":"Weather Underground",
         "link":"http://www.wunderground.com"
     }
}]

如果使用List，请在方括号[]处注意。即使只有一件商品，您的"current_observation"仍需要申报List<T>。

我建议您使用本网站：http://www.jsonschema2pojo.org/

选择Source Type: JSON，Annotation style: Moshi（我使用Moshi，或者您可以使用Gson），勾选：Make class serialiable

它会为你的json生成正确的Class。你的其余代码应该是正确的。

<强>更新：如果生成类后没有生成List，则不应使用

List<Items> items = response.body().getItems();

但是

Items items = response.body().getItems();

Answer 3

CurrentObservation.class

public class CurrentObservation {

@SerializedName("image")
@Expose
private Image1 image;

public Image1 getImage() {
return image;
}

public void setImage(Image1 image) {
this.image = image;
}
}

Example.java

public class Example {

@SerializedName("current_observation")
@Expose
private CurrentObservation currentObservation;

public CurrentObservation getCurrentObservation() {
return currentObservation;
}

public void setCurrentObservation(CurrentObservation currentObservation) {
this.currentObservation = currentObservation;
}
}

Image1.java

public class Image1 {

@SerializedName("url")
@Expose
private String url;
@SerializedName("title")
@Expose
private String title;
@SerializedName("link")
@Expose
private String link;

public String getUrl() {
return url;
}

public void setUrl(String url) {
this.url = url;
}

public String getTitle() {
return title;
}

public void setTitle(String title) {
this.title = title;
}

public String getLink() {
return link;
}

public void setLink(String link) {
this.link = link;
}

}

在主要活动

中调用它

  Call<Example> ex = BaseUrlClass.getInterface().ex("whatever parameters");
    ex.enqueue(new Callback<Example>() {
        @Override
        public void onResponse(Call<Example> call, Response<Example> response) {
            Example list = response.body();

            CurrentObservation a = list.getCurrentObservation();
            List<Image1> im = a.getImage();
            for (int i = 0;i<im.size();i++){
                Image1 image1= im.get(i);
                String a = image1.getTitle();
                String b = image1.getUrl();
                String c = image1.getLink();
            }
        }

        @Override
        public void onFailure(Call<Example> call, Throwable t) {

        }
    });

最后在你的界面

public interface ApiUtils {

@GET("")  //whatever url
Call<Example> ex();  //or any parameter
}

Answer 4

对于JSON解析，您应该使用JASONSCHEMA2POJO将JSON字符串转换为模型类

在改装成功回复中

 CurrentObservation observation = new CurrentObservation  ();
 JSONObject jsonObject = new JSONObject(response.body().string());
 observation = new Gson().fromJson(jsonObject.getString("current_observation"),CurrentObservation .class);

模型类赞

public class Example {

@SerializedName("current_observation")
@Expose
private CurrentObservation currentObservation;

public CurrentObservation getCurrentObservation() {
return currentObservation;
}

 public void setCurrentObservation(CurrentObservation currentObservation) {
 this.currentObservation = currentObservation;
 }

}

Answer 5

我如何在主要活动中调用它？

你需要像这样调用pojo类方法

String url=getCurrentObservation().getImage().getUrl();

如果你得到回复

String url=response.body().getCurrentObservation().getImage().getUrl();

要获得更多帮助，请使用我的ans

关注this link

Answer 6

我详细查看了你的Json String。只看你的＆＃34;图像＆＃34;键后跟一个JSONObject。

{
     "current_observation": {
       "image": {
             "url":"http://icons.wxug.com/graphics/wu2/logo_130x80.png",                
             "title":"Weather Underground",
             "link":"http://www.wunderground.com"
},
              {
              "url":"http://icons.wxug.com/graphics/wu2/logo_130x80.png",               
             "title":"Weather Underground",
             "link":"http://www.wunderground.com"
               }

     }
 }

因为你的＆＃34;图像＆＃34; key有多个值，它应该在JSONArray中。所以你的String应该看起来像

{
     "current_observation": {
       "image": [{
             "url":"http://icons.wxug.com/graphics/wu2/logo_130x80.png",                
             "title":"Weather Underground",
             "link":"http://www.wunderground.com"
  },
              {
              "url":"http://icons.wxug.com/graphics/wu2/logo_130x80.png",               
             "title":"Weather Underground",
             "link":"http://www.wunderground.com"
               }
         ]

     }
 }

我建议您再次检查字符串。

如何使用Retrofit解析嵌套的json ....

6 个答案: