Question

我正在尝试以下方法：

<?php
$sql = "SELECT * FROM (SELECT ID, `LAST NAME` AS lm, `FIRST NAME` AS fm FROM `OLD`";
$sql .= " UNION ALL SELECT ID, `Last Name` AS lm, `First Name` AS fm, FROM `NEW`) ";

$sth = $dbh->prepare($sql);
$params = array();
$sth->execute($params);
$ids = $lm = $fm = $dp = $ex = $bp = $em = array();
$counter = 0;
while ($row = $sth->fetch()) {

    $ids[] = $row['ID'];
    $lm[] = $row['lm'];
    $fm[] = $row['fm'];

    $counter++;
}

for($j=0;$j < $counter;$j++) {
    $new = "INSERT INTO MYTABLE (ID, lastname, firstname)";
    $new.= " VALUES( '".$ids[$j]."', '".$lm[$j]."', '".$fm[$j]."')";
    $stmt = sqlsrv_query($conn, $new);
    if( !$stmt ) {
        die( print_r( sqlsrv_errors(), true));
    } 
}
?>

这显示以下错误：

数组（[0] =＆gt;数组（[0] =＆gt; 42000 [SQLSTATE] =＆gt; 42000 [1] =＆gt; 102 [代码] =＆gt; 102 [2] =＆gt; [微软] [SQL Server的ODBC驱动程序11] [SQL 服务器]＆＃39;附近的语法不正确＆＃39;。 [message] =＆gt; [Microsoft] [ODBC驱动程序 11 for SQL Server] [SQL Server]＆＃39;附近的语法不正确＆＃39;。））

在我的for循环中，如果我尝试回显$ lm [$ j]和$ fm [$ j]变量，我会正常得到我的结果，但由于某种原因查询没有执行。

有什么想法吗？

提前谢谢

执行php脚本到sql数据库时出错

0 个答案: